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Delvig [45]
3 years ago
14

A sinusoidal electromagnetic wave is propagating in a vacuum in the +z-direction.Part AIf at a particular instant and at a certa

in point in space the electric field is in the +x-direction and has a magnitude of 4.90 V/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time?Part B
What is the direction of the magnetic field?
Physics
1 answer:
stira [4]3 years ago
8 0

Explanation:

Given that,

Magnitude of electric field in +x direction, E = 4.9 V/m

Part A :

The relation between electric and magnetic field is given by :

B=\dfrac{E}{c}

c is the speed of light

B=\dfrac{4.9\ V/m}{3\times 10^8\ m/s}

B=1.63\times 10^{-8}\ T

So, the magnetic field of the wave at this same point in space and instant in time is 1.63\times 10^{-8}\ T.\

Part B :

The direction of electric and magnetic field is same i.e. +x direction.

Hence, this is the required solution.

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an empty density bottle weighed 23.5 and 48.4g when filled with water .The empty bottle was partially filled with sand until and
gavmur [86]

Answer:

Density of Sand is 2.653g/cm^{3}.

Explanation:

Given Empty Density bottle weighs 23.5gm(W=23.5gm)

Weight of bottle when completely filled water=48.4gm

So amount of water required to fill the bottle=Weight of bottle filled with water-W

Amount of water required to fill the bottle(w_{max})=48.4gm-23.5gm

w_{max}=24.9g

Since we know density of water d_{w} =1g/cm^{3} and w_{max}

We can calculate volume of empty space in the bottle(V).

w_{max}=d_{w}\timesV

V=\frac{w_{max} }{d_{w} }

V=\frac{24.9}{1}

V=24.9 g/cm^{3}

Now bottle is partially filled with sand,and weight of bottle is (w_{s})36.5gm

So,

Amount of sand added (m_{s})=36.5-Weight of the bottle

m_{s}=13g

After filling the bottle with water again,the weight of the bottle becomes (W_{2}=56.5g)

Therefore,

amount of water added to the bottle of sand in grams = W_{2}-36.5gm

amount of water added =56.5g-36.5g

amount of water added =20g

As the density of water = 1g/cm^{3}

Amount of water (in grams )=Volume of water occupied

20=volume of water added

Therfore volume of water added to the sand filled bottle(V_{w})=20cm^{3}

As we know the total volume of the water bottle(V),

Volume of the sand occupied in the water bottle=V-V_{w}

V_{s}=24.9g-20g

V_{s}=4.9g

We know,

Density=Mass/Volume

Therefore,

density of sand = \frac{m_{s} }{V_{s} }

density of sand =\frac{13}{4.9}

density of sand = 2.653g/cm^{3}

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