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Delvig [45]
3 years ago
14

A sinusoidal electromagnetic wave is propagating in a vacuum in the +z-direction.Part AIf at a particular instant and at a certa

in point in space the electric field is in the +x-direction and has a magnitude of 4.90 V/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time?Part B
What is the direction of the magnetic field?
Physics
1 answer:
stira [4]3 years ago
8 0

Explanation:

Given that,

Magnitude of electric field in +x direction, E = 4.9 V/m

Part A :

The relation between electric and magnetic field is given by :

B=\dfrac{E}{c}

c is the speed of light

B=\dfrac{4.9\ V/m}{3\times 10^8\ m/s}

B=1.63\times 10^{-8}\ T

So, the magnetic field of the wave at this same point in space and instant in time is 1.63\times 10^{-8}\ T.\

Part B :

The direction of electric and magnetic field is same i.e. +x direction.

Hence, this is the required solution.

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The stopcock connecting a 2.14 L bulb containing oxygen gas at a pressure of 8.19 atm, and a 9.84 L bulb containing krypton gas
marshall27 [118]

Answer : The final pressure of the system in atm is, 3.64 atm

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1+P_2V_2=P_fV_f

where,

P_1 = first pressure = 8.19 atm

P_2 = second pressure = 2.65 atm

V_1 = first volume = 2.14 L

V_2 = second volume = 9.84 L

P_f = final pressure = ?

V_f = final volume = 2.14 L  + 9.84 L = 11.98 L

Now put all the given values in the above equation, we get:

8.19atm\times 2.14L+2.65atm\times 9.84L=P_f\times 11.98L

P_f=3.64atm

Therefore, the final pressure of the system in atm is, 3.64 atm

4 0
3 years ago
When preparing to strip insulation in order to splice conductors, a person should strip the insulation back far enough so that t
Fiesta28 [93]

Answer:

Closely fits into the connector.

Explanation:

It's one of the steps used for the splicing of aluminium conductors in the underground connections. Where we do the strip insulation to splice the conductors by using compression type connectors.

3 0
3 years ago
Identify where the solid would be found after distillation is complete.
dimaraw [331]

Bottom of the distillation flask

Explanation:

The solid in the mixture to be separate would be found at the bottom of the distillation flask.

Distillation is a separation technique for differentiating the components of mixtures based on the differences in their boiling points.

  • Distillation is used to recover solvents from solution.
  • The solutes are then left behind in the flask as the solvent boils out as vapor.
  • The solution is boiled in a distillation flask to vaporize the solvent.
  • The vapor is made to condense back into liquid by means of a condenser.
  • The pure liquid called distillate is collected in the receiver.
  • The solute which is the solid remains in the distillation flask

learn more:

Heterogeneous mixtures brainly.com/question/1446244

Pure substances brainly.com/question/1832352

#learnwithBrainly

8 0
3 years ago
A glass flask whose volume is 1000 cm^3 at a temperature of 1.00°C is completely filled with mercury at the same temperature. W
Marat540 [252]

Answer:

the coefficient of volume expansion of the glass is \mathbf{  ( \beta_{glass} )= 1.333 *10^{-5} / K}

Explanation:

Given that:

Initial volume of the glass flask = 1000 cm³ = 10⁻³ m³

temperature of the glass flask and mercury= 1.00° C

After heat is applied ; the final temperature = 52.00° C

Temperature change ΔT = 52.00° C - 1.00° C = 51.00° C

Volume of the mercury overflow = 8.50 cm^3 = 8.50 ×  10⁻⁶ m³

the coefficient of volume expansion of mercury is 1.80 × 10⁻⁴ / K

The increase in the volume of the mercury =  10⁻³ m³ ×  51.00 × 1.80 × 10⁻⁴

The increase in the volume of the mercury = 9.18*10^{-6} \ m^3

Increase in volume of the glass =  10⁻³ × 51.00 × \beta _{glass}

Now; the mercury overflow = Increase in volume of the mercury - increase in the volume of the flask

the mercury overflow = (9.18*10^{-6}  -  51.00* \beta_{glass}*10^{-3})\ m^3

8.50*10^{-6} = (9.18*10^{-6}  -51.00* \beta_{glass}* 10^{-3} )\ m^3

8.50*10^{-6} - 9.18*10^{-6} = ( -51.00* \beta_{glass}* 10^{-3} )\ m^3

-6.8*10^{-7} =  ( -51.00* \beta_{glass}* 10^{-3} )\ m^3

6.8*10^{-7} =  ( 51.00* \beta_{glass}* 10^{-3} )\ m^3

\dfrac{6.8*10^{-7}}{51.00 * 10^{-3}}=  ( \beta_{glass} )

\mathbf{  ( \beta_{glass} )= 1.333 *10^{-5} / K}

Thus; the coefficient of volume expansion of the glass is \mathbf{  ( \beta_{glass} )= 1.333 *10^{-5} / K}

5 0
3 years ago
Lionel makes a graphic organizer to compare the electric field around a positive charge with the electric field around a negativ
krek1111 [17]
X- points away from the charge
y- points in the direction of the force on the positive charge
z- points toward the charge
6 0
2 years ago
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