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Delvig [45]
4 years ago
14

A sinusoidal electromagnetic wave is propagating in a vacuum in the +z-direction.Part AIf at a particular instant and at a certa

in point in space the electric field is in the +x-direction and has a magnitude of 4.90 V/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time?Part B
What is the direction of the magnetic field?
Physics
1 answer:
stira [4]4 years ago
8 0

Explanation:

Given that,

Magnitude of electric field in +x direction, E = 4.9 V/m

Part A :

The relation between electric and magnetic field is given by :

B=\dfrac{E}{c}

c is the speed of light

B=\dfrac{4.9\ V/m}{3\times 10^8\ m/s}

B=1.63\times 10^{-8}\ T

So, the magnetic field of the wave at this same point in space and instant in time is 1.63\times 10^{-8}\ T.\

Part B :

The direction of electric and magnetic field is same i.e. +x direction.

Hence, this is the required solution.

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Answer:

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The value of radial acceleration \alpha_{r} = 80 \frac{m}{s^{2} }

Explanation:

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Radius of the disk = 0.8 m

Angular velocity = 10 \frac{rad}{s}

We know that tangential acceleration is given by the formula \alpha_{t} = r \alpha

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⇒ \alpha_{t} = 0.8 × 50

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Radial acceleration is given by

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⇒ V = 0.8 × 10

⇒ V = 8 \frac{m}{s}

Radial acceleration

\alpha_{r} = \frac{8^{2} }{0.8}

\alpha_{r} = 80 \frac{m}{s^{2} }

This is the value of radial acceleration.

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