What is the moment of inertia i of this assembly about the axis through which it is pivoted?
1 answer:
Answer:
I =
Explanation:
The moment of inertia for the beam is:
I =
Where is the mass of the beam and L is the lengh of the beam
note:
L = 2x
And for particles I is equal to:
I = MR^2
where M is the mass of the particle and R is the distance between the pivot and the particle.
Finally, the moment of inertia for this assembly is the sum of the moment of inertia of the particles and the beam. So:
I =
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Answer:
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Let's denote the distance between particles 1 and 3 as x. Therefore the distance between particles 2 and 3 is (0.1 - x), since the distance between 1 and 2 is 0.1 m.
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The question asks that , so
We will take the positive root:
away from the first particle.
Explanation:
Since Fig. 21-25 is not given in the question, the exact locations are not known. However, the location of the third particle is found to be 0.036 m away from the first particle and the third particle is located between the particles 1 and 2.