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Mekhanik [1.2K]
3 years ago
6

To create an element, a(n) _______________ reaction must take place. electromagnetic gravitational chemical nuclear

Chemistry
1 answer:
Alborosie3 years ago
4 0
A chemical reaction is the rearrangement of the molecular or ionic structure of an element.
A nuclear reaction is a change in identity or characteristics of an atomic nucleus that is reacted when being hit with an energy particle extremely hard.
I believe it is nuclear reaction.
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Determine the molar solubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 Ă— 10-13. Determine the molar sol
Kaylis [27]

Hey there!:

Given the reaction:

 NaBr  ⇌  Na⁺ +  Br⁻

  ↓              ↓         ↓

0.150M      0.150M     0.150M


AgBr ⇌ Ag⁺   + Br⁻

 ↓            ↓          ↓

 x            x         0.150M


Therefore:

Ksp = x * 0.150

x = ( 7.7 * 10⁻¹³ ) / 0.150

x = 5.1 * 10⁻¹²


Answer B


Hope that helps!

5 0
3 years ago
In the balanced reaction and using the mole ratio:
NikAS [45]

12 moles are needed because stoichiometry is 1:2

D

4 0
4 years ago
Write the ground state electron configuration of zn using the noble-gas shorthand notation.
V125BC [204]
Atomic Number of Zinc is 30, means it contains 30 electrons. So, its electronic configuration is as follow,

                                    1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰
As,
          1s², 2s², 2p⁶, 3s², 3p⁶  =  Argon
So,
Electronic configuration of Zinc in shorthand notation is as follow,

                                     [Ar] 4s², 3d¹⁰
8 0
3 years ago
Why are pennies good for simulating radioactive atoms? Check all that apply
gavmur [86]

Answer:

all of them are correct.

Explanation:

Just took it on e2020

5 0
3 years ago
Calculate the pH during the titration of 30.00 mL of 0.1000 M HCOOH(aq) with 0.1000 M NaOH(aq) after 29.3 mL of the base have be
pashok25 [27]

Answer:

3.336.

Explanation:

<em>Herein, the no. of millimoles of the acid (HCOOH) is more than that of the base (NaOH).</em>

<em />

So, <em>concentration of excess acid = [(NV)acid - (NV)base]/V total</em> = [(30.0 mL)(0.1 M) - (29.3 mL)(0.1 M)]/(59.3 mL) = <em>1.18 x 10⁻³ M.</em>

<em></em>

<em> For weak acids; [H⁺] = √Ka.C</em> = √(1.8 x 10⁻⁴)(1.18 x 10⁻³ M) = <em>4.61 x 10⁻⁴ M.</em>

∵ pH = - log[H⁺].

<em>∴ pH = - log(4.61 x 10⁻⁴) = 3.336.</em>

7 0
4 years ago
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