Hey there!:
Given the reaction:
NaBr ⇌ Na⁺ + Br⁻
↓ ↓ ↓
0.150M 0.150M 0.150M
AgBr ⇌ Ag⁺ + Br⁻
↓ ↓ ↓
x x 0.150M
Therefore:
Ksp = x * 0.150
x = ( 7.7 * 10⁻¹³ ) / 0.150
x = 5.1 * 10⁻¹²
Answer B
Hope that helps!
12 moles are needed because stoichiometry is 1:2
D
Atomic Number of Zinc is 30, means it contains 30 electrons. So, its electronic configuration is as follow,
1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰
As,
1s², 2s², 2p⁶, 3s², 3p⁶ = Argon
So,
Electronic configuration of Zinc in shorthand notation is as follow,
[Ar] 4s², 3d¹⁰
Answer:
3.336.
Explanation:
<em>Herein, the no. of millimoles of the acid (HCOOH) is more than that of the base (NaOH).</em>
<em />
So, <em>concentration of excess acid = [(NV)acid - (NV)base]/V total</em> = [(30.0 mL)(0.1 M) - (29.3 mL)(0.1 M)]/(59.3 mL) = <em>1.18 x 10⁻³ M.</em>
<em></em>
<em> For weak acids; [H⁺] = √Ka.C</em> = √(1.8 x 10⁻⁴)(1.18 x 10⁻³ M) = <em>4.61 x 10⁻⁴ M.</em>
∵ pH = - log[H⁺].
<em>∴ pH = - log(4.61 x 10⁻⁴) = 3.336.</em>
