Answer: The net ionic equation for the cobalt-silver voltaic cell is
Explanation: In cobalt-silver voltaic cell, one half of the cell consists of cobalt electrode immersed in solution ( which means that are present in the solution) and other half of the cell consists of the Ag electrode immersed in solution ( which means that is present in the solution)
The two electrodes are joined by the copper wire. The cobalt electrode acts as an anode and the silver electrode acts a cathode.
At anode, oxidation reaction takes place and at cathode, reduction reaction takes place.
At Anode :
At Cathode:
Net ionic equation:
Explanation:
Radium (atomic number 88) has similar properties to barium and is also in the Group 2 category. However, radium is a radioactive element and is generally under the category of radioisotopes in addition to being an alkaline earth metal, because it is not a stable element.
The answer is (2). You can think about this question in terms of the Bohr's model of the atom or in terms of quantum chemistry. In the Bohr model, electrons exist in discrete "shells," each respresenting a fixed spherical distance from the nucleus in which electrons of certain energy levels orbit the nucleus. The larger the shell (the greater the "orbit" radius), the greater the energy of the "orbiting" electron (I use quotations because electrons don't actually orbit the nucleus in the traditional sense, as you may know). Thus, according to the Bohr model, a third shell electron should be farther from the nucleus and have greater energy than an electron in the first shell.
The quantum model is differs drastically from the Bohr model in many ways, but the essence is the same. A larger principal quantum number indicates 1) greater overall energy and 2) a probability distribution spread a bit more outward.
The molar mass of this gas is 92.3 g/mol
Calculation
By use ideal gas equation PV =nRT where
n=mole p=pressure V= volume R = gas constant T= temperature
n = mass /molar mass(MM)
substitute in the equation
PV =(mass/MM)RT
mass = density x volume(V)
Therefore PV =(density xV/ MM) xRT
divide both side by by V
P= (density/Mm) xRT
making MM the subject of the formula
MM = densityPRT
At STP = P= 1 atm, R= 0.0821 L.atm/Mol.k T = 273 K
MM is therefore = 4.12 g/l x 1 atm x 0.081 L.atm/mol.k x 273 K = 92.3 g/mol
Answer:
Esterification reaction
Explanation:
When we have to go from an acid to an ester we can use the <u>esterification reaction</u>. On this reaction, an alcohol reacts with a carboxylic acid on acid medium to produce an ester and water. (See figure).
In this case, we need the <u>methyl ester</u>, therefore we have to choose the <u>appropriate alcohol</u>, so we have to use the <u>methanol</u> as reactive if we have to produce the methyl ester.