Answer:
1) ∫ x² e^(x) dx
4) ∫ x cos(x) dx
Step-by-step explanation:
To solve this problem, eliminate the choices that can be solved by substitution.
In the second problem, we can say u = x², and du = 2x dx.
∫ x cos(x²) dx = ∫ ½ cos(u) du
In the third problem, we can say u = x², and du = 2x dx.
∫ x e^(x²) dx = ∫ ½ e^(u) du
I'm going to go right ahead and assume that we're talking about a linear equation.
The linear equation passing through the points given is y=3x+4, since it satisfies both of the points given.
I dont know the coordinates because i dont feel like putting them in right now buttttt........
main street bus equation is y=2x+40
County bus line equation is y=3x+20
thats all i've got.
That is a perpendicular bisector
Yes they are proportionate
