Answer:
1) The final displacement of cyclist is 20.8 km.
2) The average velocity of cyclist is 18.35 m/h
Explanation:
The path traced by the cyclist is as shown in the attached figure
from the attached figure we can see
1) Initial distance covered = 8.0 km east therefore OA = 8.0 km
2) When the cyclist turns and travels 3.2 km west thus AB = 3.2 km
3) From B the cyclist turns and travels 16 km east thus BC = 16.0 km
As we can see that the total displacement is OC = OA- AB + BC = 8.0-3.2+16 = 20.8 km
Thus the final displacement is 20.8 km.
Part b)
By definition of average velocity we have
They can tell what type/species the dinosaur was
Answer:
1.424 μC
Explanation:
I'm assuming here, that the charged ball is suspended by the string. If the string also is deflected by the angle α, then the forces acting on it would be: mg (acting downwards),
tension T (acting along the string - to the pivot point), and
F (electric force – acting along the line connecting the charges).
We then have something like this
x: T•sin α = F,
y: T•cosα = mg.
Dividing the first one by the second one we have
T•sin α/ T•cosα = F/mg, ultimately,
tan α = F/mg.
Since we already know that
q1=q2=q, and
r=2•L•sinα,
k=9•10^9 N•m²/C²
Remember,
F =k•q1•q2/r², if we substitute for r, we have
F = k•q²/(2•L•sinα)².
tan α = F/mg =
= k•q²/(2•L•sinα)² •mg.
q = (2•L•sinα) • √(m•g•tanα/k)=
=(2•0.5•0.486) • √(0.0142•9.8•0.557/9•10^9) =
q = 0.486 • √(8.61•10^-12)
q = 0.486 • 2.93•10^-6
q = 1.424•10^-6 C
q = 1.424 μC.
Answer: 2.13 E 4 J
Explanation: Heat absorbed = mass * specific heat capacity * change in temperature
= 0.5 * 387 * (400 - 290) J
= 0.5 * 387 * 110 J = 21285 J = 2.13 E 4 J
The area between the 10 and the 12.