Answer:
25.82 m/s
Explanation:
We are given;
Force exerted by baseball player; F = 100 N
Distance covered by ball; d = 0.5 m
Mass of ball; m = 0.15 kg
Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.
We should note that work done is a measure of the energy exerted by the baseball player.
Thus;
F × d = ½mv²
100 × 0.5 = ½ × 0.15 × v²
v² = (2 × 100 × 0.5)/0.15
v² = 666.67
v = √666.67
v = 25.82 m/s
Frequency = (speed) / (wavelength)
Speed = 3 x 10⁸ m/s
Wavelength = 3 cm = 0.03 m
Frequency = (3 x 10⁸ m/s) / (0.03 m)
Frequency = (3 x 10⁸ / 0.03) (m / m-s)
Frequency = 1 x 10¹⁰ Hz (10 Gigahertz)
Answer:
Explanation:
Formula to calculate the distance between two points
and
is,
d = 
Therefore, length of CD having coordinates C(3,1) and D(3, 3),
CD = 
= 2 units
Formula to find the midpoint of CD is,
M = 
= 
= (3, 2)
Therefore, length of CD = 2 units and (3, 2) are the coordinates of the midpoint of CD.
Answer:
The wavelength of the sound waves are, λ = 26.92 m
Explanation:
Given data,
The frequency of the sound waves, f = 13 Hz
The speed of sound waves in air, v = 350 m/s
The velocity of the wave in the medium is equal to the product of its wavelength and its frequency.
The formula for the wavelength of the waves is,
λ = v / f
Substituting the given values in the above equations,
λ = 350 m/s / 13 Hz
= 26.92 m
Hence, the wavelength of the sound waves are, λ = 26.92 m
Answer:
The equation a=F/m or the acceleration is equal to the net force of an object divided by that object's mass, is an equation derived and explained by Sir Issac Newton's second law of motion. Newton's second law of motion states that the force of an object is equal to the mass times the acceleration of that object.