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3 years ago

What can a paleontologist tell from fossil footprints of a dinosaur

Physics

2 answers:

weeeeeb [17]3 years ago

8 0

They can tell what type/species the dinosaur was

AfilCa [17]3 years ago

7 0

Answer:

IDK

Explanation:

Sorry But I not sorry!!!!!!!!!!

LOL:}

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The note created by a flute will increase the speed of sound increases. When a marching band goes outside on a cold day, what wo

alexgriva [62]

A).

It would decrease because the speed of sound and temperature are proportional.

4 0

3 years ago

Read 2 more answers

During adverse weather conditions such as rain or fog, drivers should take action accordingly by turning on their headlights, sl

xeze [42]

<span>During adverse weather conditions such as rain or fog, drivers should take action accordingly by turning on their headlights, slowing down and increasing following distance. Adverse weather means that you are driving in difficult and dangerous conditions. Increasing following distance will help you to maintain safe driving and avoid tailgating. </span>

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3 years ago

In a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to a screen is

meriva

The spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

<h3>What is double slit experiment?</h3>

The double-slit experiment serves as a proof in current physics that both light and matter may exhibit properties of classically defined waves and particles. It also illustrates the inherently probabilistic nature of quantum mechanical events. Thomas Young carried out the first experiment of this kind employing light in 1802, illustrating how light behaves like a wave. It was formerly believed that light was made up of either waves or particles. About a century later, with the advent of modern physics, it was discovered that light may in fact exhibit behaviour like that of both waves and particles. The identical behaviour of electrons was first shown by Davisson and Germer in 1927, and it was later extended to atoms and molecules.

The separation between the slits, d = 0.05mm = 5×10⁻⁵ m

The distance from the slits to a screen, D = 2.5 m

Let x is the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits,

λ = 600nm = 6× 10⁻⁷ m

We know that the bright fringe is given by :

y = nλD/d

So, the spacing between the first-order and second-order bright fringes is :

x = 2λD/d - λD/d

x = λD/d

x = 6 × 10⁻⁷ × 2.5/5 × 10⁻⁵

x = 0.03 m

x = 3 cm

So, the spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

to learn more about double slit experiment go to -

brainly.com/question/28108126

#SPJ4

8 0

1 year ago

After being struck by a bowling ball, a 1.3 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.3 kg

GuDViN [60]

Answer:

a) 4.2m/s

b) 5.0m/s

Explanation:

This problem is solved using the principle of conservation of linear momentum which states that in a closed system of colliding bodies, the sum of the total momenta before collision is equal to the sum of the total momenta after collision.

The problem is also an illustration of elastic collision where there is no loss in kinetic energy.

Equation (1) is a mathematical representation of the the principle of conservation of linear momentum for two colliding bodies of masses $m_1$ and $m_2$ whose respective velocities before collision are $u_1$ and $u_2$ ;

$m_1u_1+m_2u_2=m_1v_1+m_2v_2..............(1)$

where $v_1$ and $v_2$ are their respective velocities after collision.

Given;

$m_1=1.3kg\\u_1=5m/s\\m_2=1.3kg\\u_2=0m/s$

Note that $u_2$ =0 because the second mass $m_2$ was at rest before the collision.

Also, since the two masses are equal, we can say that $m_1=m_2=m$ so that equation (1) is reduced as follows;

$mu_1+mu_2=mv_1+mv_2\\\\m(u_1+u_2)=m(v_1+v_2)..............(2)$

m cancels out of both sides of equation (2), and we obtain the following;

$u_1+u_2=v_1+v_2.............(3)$

a) When $v_1=0.8m/s$ , we obtain the following by equation(3)

$5+0=0.8+v_2\\hence\\v_2=5-0.8\\v_2=4.2m/s$

b) As $m_1$ stops moving $v_1=0$ , therefore,

$5+0=0+v_2\\v_2=5m/s$

5 0

3 years ago

Hydrogen line spectrum lies entirely within visible range

mart [117]

No, that's silly.

You've got your Pfund series where electrons fall down to the 5th level,
your Brackett series where they fall to the 4th level, and your Paschen
series where they fall to the 3rd level. All of those transitions ploop out
photons at Infrared wavelengths.

THEN next you get your Balmer series, where the electrons fall in
to the 2nd level. Most of those are at visible wavelengths, but even
a few of the Balmer transitions are in the Ultraviolet.

And then there's the Lyman series, where electrons fall all the way
down to the #1 level. Those are ALL in the ultraviolet.

6 0

3 years ago