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maxonik [38]
3 years ago
9

Which two would likely bond to form a salt?

Chemistry
2 answers:
attashe74 [19]3 years ago
8 0

Answer:

B. Mg and Cl

Explanation:

MAVERICK [17]3 years ago
6 0

Answer:

Mg and Cl

Explanation:

Mg + Cl ---> MgCl2 ( Magnesium Chloride )

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oksano4ka [1.4K]
I think you mean alcohol ? if so there are a few basic types including ethanol
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3 years ago
You have a solution that is 18.5% (v/v) methyl alcohol. If the bottle contains 1.64 L of solution, what is the volume (V) in mil
Juliette [100K]

Answer:

303.4 millimeters

Explanation:

Just multiply 1.64 by 0.185. then convert that answer to millimeters

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3 years ago
What is it called when an enzyme changes shape
7nadin3 [17]

Answer: Induced Fit

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4 0
2 years ago
Calculate the standard cell potential given the following standard reduction potentials: Al3++3e−→Al;E∘=−1.66 V Cu2++2e−→Cu;E∘=0
Maru [420]

Answer:

Explanation:

To calculate the cell potential we use the relation:

Eº cell = Eº oxidation + Eº reduction

Now in order to determine which of the species is going to be oxidized, we have to remember that the more the value of the reduction potential is negative,  the greater its tendency to be oxidized is. In electrochemistry we use the values of the reductions potential in the tables for simplicity  because the only thing we need to do is change the sign of the reduction potential for the oxized species .

So the species that is going to be oxidized is the Aluminium, and therefore:

Eº cell = -( -1.66 V ) + 0.340 V =  5.06 V

Equally valid is to write the equation as:

Eº cell = Eº reduction for the reduced species - Eº reduction for the oxidized species

These two expressions are equivalent, choose the one you fell more comfortable but be careful with the signs.

3 0
3 years ago
I need help. Please help with the best of your ability.​
topjm [15]

Answer:

Photosynthesis transforms light energy into chemical energy by making sugars. Cellular respiration releases the chemical energy from food by breaking down sugars.

Explanation:

I'm actually learning this in school right now

Hope this helps!

~PurpleMist

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3 years ago
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