Answer:
![4ln [\frac{x^2 (x^3-1)}{x-5}]](https://tex.z-dn.net/?f=%204ln%20%5B%5Cfrac%7Bx%5E2%20%28x%5E3-1%29%7D%7Bx-5%7D%5D)
Step-by-step explanation:
For this case we have the following expression:
![4[ln(x^3-1) +2ln(x) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%20%2B2ln%28x%29%20-ln%28x-5%29%5D)
For this case we can apply the following property:

And we can rewrite the following expression like this:

And we can rewrite like this our expression:
![4[ln(x^3-1) +ln(x^2) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%20%2Bln%28x%5E2%29%20-ln%28x-5%29%5D)
Now we can use the following property:

And we got this:
![4[ln(x^3-1)(x^2) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%28x%5E2%29%20-ln%28x-5%29%5D)
And now we can apply the following property:

And we got this:
![4ln [\frac{x^2 (x^3-1)}{x-5}]](https://tex.z-dn.net/?f=%204ln%20%5B%5Cfrac%7Bx%5E2%20%28x%5E3-1%29%7D%7Bx-5%7D%5D)
And that would be our final answer on this case.
Answer:
5.5, 9.5
Step-by-step explanation:
Let x and y be the numbers
x+y = 15
x-y = 4
Add the two equations together to eliminate y
x+y = 15
x-y = 4
------------------
2x = 19
Divide by 2
2x/2 =19/2
x = 9.5
Now find y
x+y = 15
9.5+y = 15
Subtract 9.5
x = 15-9.5
x =5.5
X^2 - 18x = -80 (add 2x to both sides)
The are adding 4 minusing 2 adding 4 then then they keep adding 4