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3 years ago

In rectangle ABCD with side AD = 6 cm, point M is the midpoint of side

1 answer:

4 0

So if the measure of angle AMB = 90 so the another right triangle is formed which is ADM, since the it is a right triangle the legs are equal, then the lenght AD = DM and we can solve the length of AM
AM = sqrt( AD^2 + DM^2)
AM = sqrt( 6^2 + 6^2)
AM = 6sqrt(2)
now we can solve the length of AB
AB = sqrt ( AM^2 + MB^2)
AB = sqrt ( 6sqrt(2)^2 + 6sqrt(2)^2)
AB = 12

so the perimeter = 2(6) + 2(12) = 36

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What is the solution to -x2 + 5x - 10 = 0?

Korolek [52]

Answer:

No solution

Explanation

−x^2+5x−10=0

Step 1: Use quadratic formula with a=-1, b=5, c=-10.

you plug it in as shown below

and simplify

when you simplify

you get

as shown below

This is no solution....

7 0

3 years ago

How many solutions y= -2x -4 and y=3x plus 3

Oksi-84 [34.3K]

Answer:

The number of solutions is one

Step-by-step explanation:

Here, we want to get the number of solutions

since the linear equations are not the same, neither do they have the same x-variable, we can have only one solution

6 0

3 years ago

A cylinder has a radius of 20 cm and a height of 2 cm. Find the height of another cylinder that has a radius of 4 cm and the sam

iogann1982 [59]

Answer:

The height of the another cylinder 'h' = 7

Step-by-step explanation:

<u>Explanation</u>:-

Surface area of the cylinder = 2пrh + 2пr^2

Given radius of first cylinder is 20cm

given height of the first cylinder is 2 cm

The surface area of first cylinder is = 2пrh + 2пr^2

= 2п(20)(2)+2п(2)^2

= 4п(20+2)

The surface area of first cylinder is 88п

<u>Step 2</u>:

given data The surface area of first cylinder is 88п is same as second cylinder also

<u>Find the height of the second cylinder</u>

Given Radius of the second cylinder r = 4

Surface area of the cylinder = 2пrh + 2пr^2 = 88п

2п(4)h+2п(4)^2 =88п

on simplification we get

2п (4h+16) = 88п

after cancellation '2п' value and on simplification, we get

4h+16 = 44

4h = 44-16

4h = 28

h=7

Therefore the height of the another cylinder is 'h' =7

3 0

4 years ago

A survey asked 20 mobile phone dealers how many mobile phones were sold during the previous week. Their answers are displayed in

Sidana [21]

The best type of chart for quickly deriving the mode of a sample data is called the Stem-and-Leaf Plot.

In statistics, the Stem-and-Leaf Plot is an easy-to-make easy-to-read kind of graph that is derived from the table holding the sample data.

The Box-and-Whisker Plot on the other hand is best for visually depicting the five-number summary of any set of data, which are:

Minimum
First Quartile
Median (Second Quartile)
Third Quartile; and
Maximum.

It is to be noted that referenced plots are not indicated hence, the general answer.

Learn more about Stem-and-Leaf Plot at:
brainly.com/question/8649311
#SPJ1

8 0

2 years ago

Find y' by implicit differentiation √x +√y =1

AleksandrR [38]

Differentiate both sides with respect to x

$\frac{d}{dx}(x^{\frac{1}{2}} + y^{\frac{1}{2}}) = \frac{d}{dx}(1)\\\\ \frac{1}{2x^{\frac{1}{2}}} + \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0\\\\\frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}\\\\\frac{1}{2\sqrt{y}}\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \\\\\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \times 2\sqrt{y}\\\\\frac{dy}{dx} = -\frac{\sqrt{y}}{\sqrt{x}} \\\\\boxed{\bf{y'= -\frac{\sqrt{y}}{\sqrt{x}}}}$

5 0

3 years ago