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3 years ago

In rectangle ABCD with side AD = 6 cm, point M is the midpoint of side

1 answer:

4 0

So if the measure of angle AMB = 90 so the another right triangle is formed which is ADM, since the it is a right triangle the legs are equal, then the lenght AD = DM and we can solve the length of AM
AM = sqrt( AD^2 + DM^2)
AM = sqrt( 6^2 + 6^2)
AM = 6sqrt(2)
now we can solve the length of AB
AB = sqrt ( AM^2 + MB^2)
AB = sqrt ( 6sqrt(2)^2 + 6sqrt(2)^2)
AB = 12

so the perimeter = 2(6) + 2(12) = 36

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el jefe decidió agregar la tabla de frecuencias correspondiente a la edad de sus empleados tal Como se muestra a continuación Cu

lapo4ka [179]

Answer:

Average employee [Mean] = 43.6

Step-by-step explanation:

Given:

Interval Number of employee

25-35 20

35-45 7

45-55 8

55-65 15

Total 50

Find:

Average employee [Mean]

Computation:

Interval X[u+l]/2 Number of employee fx

25-35 30 20 600

35-45 40 7 280

45-55 50 8 400

55-65 60 15 900

Total 50 2,180

Average employee [Mean] = Sum of fx / Sum of x

Average employee [Mean] = 2,180 / 50

Average employee [Mean] = 43.6

5 0

3 years ago

The quality control manager of a chemical company randomly sampled twenty 100-pound bags of fertilizer to estimate the variance

lisabon 2012 [21]

Answer:

The 95% confidence interval for the variance in the pounds of impurities would be $3.829 \leq \sigma^2 \leq 14.121$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =6.62$ represent the sample variance

s=2.573 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical values.