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xz_007 [3.2K]
3 years ago
7

In general how are word equations written to describe chemical equations

Chemistry
1 answer:
Alexus [3.1K]3 years ago
5 0
 <span>chemicals reacting are written on the left, what is formed is written on the right after the = sign 

eg Copper + oxygen = copper oxide.
Hope this helps , mark as brainliest and say thanks THANKS..</span>
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You could add solid KCl to the solution to precipitate out AgCl(s). What mass of KCl is needed to precipitate the silver ions fr
padilas [110]

Answer:

0.143 g of KCl.

Explanation:

Equation of the reaction:

AgNO3(aq) + KCl(aq) --> AgCl(s) + KNO3(aq)

Molar concentration = mass/volume

= 0.16 * 0.012

= 0.00192 mol AgNO3.

By stoichiometry, 1 mole of AgNO3 reacts with 1 mole of KCl to form a precipitate.

Number of moles of KCl = 0.00192 mol.

Molar mass of KCl = 39 + 35.5

= 74.5 g/mol

Mass = molar mass * number of moles

= 74.5 * 0.00192

= 0.143 g of KCl.

4 0
3 years ago
How is beryllium similar to calcium?<br>​
Molodets [167]

Answer:

The second column on the periodic table of the chemical elements is collectively called the alkaline earth metal group: beryllium, magnesium, calcium, strontium, barium, and radium. Because the outer electron structure in all of these elements is similar, they all have somewhat similar chemical and physical properties.

Explanation:

8 0
2 years ago
¡¡¡PLEASE HELP!!! I'm stuck on a question..
Reptile [31]

 The half  life  of uranium- 238  is

 4.46 x10^9  years


 Explanation

Half life  is the time  taken for  the  radioactivity  of   a isotope  to fall  to half  its  original  value.

The  original   mass  of uranium-238  is  4.0 mg

  Half  of original  mass of uranium  = 4.0  mg /2 = 2.0  mg

since  it  take 4.46  x 10^ 9 years  for  the sample   to half  the half life of uranium -238 = 4.46 x10^9 years

7 0
3 years ago
A sample of carbon dioxide gas occupies a volume of 250 mL at 25c what volume will it occupy at 95c
anzhelika [568]

Considering the Charles's law, the sample of carbon dioxide gas will occupy 308.72 mL.

<h3>Charles's law</h3>

Charles's law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that the volume is directly proportional to the temperature of the gas: for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.

Mathematically, Charles's law states that the ratio between volume and temperature will always have the same value:

\frac{V}{T} =k

Considering an initial state 1 and a final state 2, it is fulfilled:

\frac{V1}{T1} =\frac{V2}{T2}

<h3>Final volume in this case</h3>

In this case, you know:

  • V1= 250 mL
  • T1= 25 C= 298 K (being 0 C=273 K)
  • V2= ?
  • T2= 95 C= 368 K

Replacing in Charles's law:

\frac{250 mL}{298 K} =\frac{V2}{368 K}

Solving:

V2=368 K\frac{250 mL}{298 K}

<u><em>V2= 308.72 mL</em></u>

Finally, the sample of carbon dioxide gas will occupy 308.72 mL.

Learn more about Charles's law:

brainly.com/question/4147359

#SPJ1

6 0
1 year ago
A stock solution of sodium sulfate NaSO4 has a concentrate of 1.00 m. The volume of this solution is 50 ml. What volume of 0.25
mylen [45]
<h3>Answer:</h3>

200 mL

<h3>Explanation:</h3>

Concept tested: Dilution formula

We are given;

  • Concentration of stock solution as 1.00 M
  • Volume of the stock solution as 50 mL
  • Molarity of the dilute solution as 0.25 M

We are required to calculate the volume of diluted solution;

  • The stock solution is the original solution before dilution while diluted solution is the solution after dilution.
  • Using the dilution formula we can determine the volume of diluted solution;

M1V1 = M2V2

Rearranging the formula;

V2 = M1V1 ÷ M2

     = (1.00 M × 50 mL) ÷ 0.25 M

     = 200 mL

Therefore, a volume of 200mL of 0.25 M solution could be made from the stock solution.

5 0
3 years ago
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