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3 years ago

In general how are word equations written to describe chemical equations

1 answer:

5 0

chemicals reacting are written on the left, what is formed is written on the right after the = sign

eg Copper + oxygen = copper oxide.
Hope this helps , mark as brainliest and say thanks THANKS..

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As the pressure on the surface of a liquid decreases, the temperature at which the liquid will boil

ankoles [38]

Answer: option (1) decreases.

Explanation:

May be you have experienced that: when you go to the beach, where the atmposhpere pressure is greater than the atmosphere pressure in places that are at higher altitudes, the water takes longer to boil. That is because the boiling temperature is greater, and you need more total heat (more time) to permit the liquid to reach that temperature.

The reason why that happens is because substances boil when the vapor pressure (the pressure of the particles of vapor over the liquid) equals the atmosphere pressure. So, when the atmposhere pressure increases, the temperature at which the vapor pressure reaches the atmosphere pressure also increases, and when the atmosphere pressure decreases, the temperature at which the vapor pressure reaches the atmosphere pressure decreases.

5 0

3 years ago

Read 2 more answers

If 251 mL of 6.0 M H2SO4 is diluted to 500. mL, what is its new molarity?

kolezko [41]

Answer:

3.0M

Explanation:

The dilution formula is:

$M_1\times V_1=M_2\times V_2$

Where M₁ and M₂ are the molar concentrations and V₁ and V₂ are the volumes of the concentrated and the diluted solutions.

Substitute:

M₁ = 6.0M

M₂ = unknown

V₁ = 251 mL

V₂ = 500. mL

$6.0M\times 251ml=M_2\times 500.ml$

Clear M₂ and compute:

$M_2=6.0M\times 251ml/500.ml\approx3.0M$

8 0

3 years ago

What is the brown liquid for that the grasshopper may “spit” out?

Mnenie [13.5K]

Tobacco juice would be your correct answer.

6 0

3 years ago

Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.

Misha Larkins [42]

Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

$moles HCl = moles KOH \\ \\ cHCl*vHCl=cKOH*vKOH \\ \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}= 541,54mL$

So, the required volume of HCl is 541,54 mL

Have a nice day!

8 0

3 years ago

Katyanochek1 [597]

Answer:

The answer to your question is V2 = 4.97 l

Explanation:

Data

Volume 1 = V1 = 4.40 L Volume 2 =

Temperature 1 = T1 = 19°C Temperature 2 = T2 = 37°C

Pressure 1 = P1 = 783 mmHg Pressure 2 = 735 mmHg

Process

1.- Convert temperature to °K

T1 = 19 + 273 = 292°K

T2 = 37 + 273 = 310°K

2.- Use the combined gas law to solve this problem

P1V1/T1 = P2V2/T2

-Solve for V2

V2 = P1V1T2 / T1P2

-Substitution

V2 = (783 x 4.40 x 310) / (292 x 735)

-Simplification

V2 = 1068012 / 214620

-Result

V2 = 4.97 l

6 0

3 years ago