Answer:
SAS
Step-by-step explanation:
Given: Two triangles ΔABD and ΔDCA,
We have, AD=AD (normal)
∠A=∠A (Given)
BA=CD (Sides inverse to rise to points are consistently equivalent)
With the SAS rule of congruency,
ΔABD≅ΔDCA
Brainliest?
He can conclude that the system of equations has no solution since one equation in it always results with false equivalency.
Hope this helps.
r3t40
Cd is equal to this: first calculate AB by sin30 which is radical 3 then by sin45 you know bc is radical 3 too then by fisaghures ( idk what you call it)
calculate bd at the end you just gotta do this: bd-bc
Answer:
<h2>x = 7 cm</h2>
Step-by-step explanation:
The perimeter of the given triangle:
P = (2x + 1) + (x + 2) + (3x - 9) and P = 36 cm.
Therefore we have the equation:
2x + 1 + x + 2 + 3x - 9 = 36 <em>combine like terms</em>
(2x + x + 3x) + (1 + 2 - 9) = 36
6x - 6 = 36 <em>add 6 to both sides</em>
6x = 42 <em>divide both sides by 6</em>
x = 7
3y = x - 1...I am going to re-arrange this.....-x + 3y = -1
-x + 3y = -1
x - 2y = 2
---------------add...u will notice that the x's cancel
y = 1
3y = x - 1
3(1) = x - 1
3 = x - 1
3 + 1 = x
4 = x
solution is (4,1)
