The first thing to take into account is that the probability of getting any of the six numbers of the dice after rolling it is the same and that probability is 1/6. Here we are being asked about the probability of getting a 1 or a 4 or a 5. In order to find it we need to define which are our favourable cases. Favourable cases are the results we want to get when we roll the dice so getting a 1, a 4 or a 5 are all favourable cases. All the other possible outcomes are unfovourable cases: getting a 2, a 3 or a 6. So we have 3 favourable and 3 unfavourable cases. Adding them we know that the total amount of cases is 6. The probability we are looking for (i'm going to call it P) is given by these quantities I defined:

So the probability written as a simplified fraction is 1/2.
Answer:
b
Step-by-step explanation:
By the Pythagorean Theorem, the hypotenuse squared is equal to the sum of the sides squared...
h^2=x^2+y^2
We are told that y=x+20 and h=24 so
x^2+(x+20)^2=24^2
x^2+x^2+40x+400=576
2x^2+40x+400=576
2x^2+40x=176
x^2+20x=88
x^2+20x+100=188
(x+10)^2=188
x+10=±√188
x=-10±√188, x>0 so
x=-10+√188 ft
y=10+√188 ft
If you want approximations...
x≈3.71 ft
y≈23.71 ft
Answer:
was that all the info gave?
Step-by-step explanation:
Answer:
32
Step-by-step explanation:
you gave me the answer :)