Help? please.........

The wingspans of Rodrigues fruit bats are normally distributed, with a mean of 82.5 centimeters and a standard deviation of 2.5

IrinaK [193]

81.5%
i honestly looked at the numbers in the problem

6 0

3 years ago

In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o

melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

C. $z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D. $z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

$\hat p=\frac{33}{363}=0.0912$ estimated proportion of orders not accurate

$p_o=0.10$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

$z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

6 0

3 years ago

Find the equations of the tangents to the curve x=9t2+3, y=6t3+3 that pass through the point (12,9).

Xelga [282]

Answer:

The equation will be " $y=x-3$ ".

Step-by-step explanation:

Given:

Points (12, 9) = (x, y)

⇒ $x=9t^2+3$

then,

$\frac{dy}{dt}=18t$

or,

⇒ $y=6t^3+3$

then,

$\frac{dy}{dt}=18t^2$

⇒ $\frac{dy}{dx}=\frac{18t^2}{18t}$

$=t$

By using the point slope form.

The equation of tangent will be:

⇒ $y-9=1(x-12)$

$y-9=x-12$

$y=x-12+9$

$y=x-3$

4 0

3 years ago

Help! <br> Expressions and equations

Dovator [93]

Answer:

1. 16−6=10

2. 4⋅2+1

3. x÷25

4. y+8=40

Explanation:

This is an equation—two expressions are connected with an .This is an expression—no equal sign. This is an expression—no equal sign. This is an equation—two expressions are connected with an equal sign.

5 0

2 years ago

How did the temp. change if at first it increased by 25% and then decreased by 40%?

antiseptic1488 [7]

Answer:

The temperature would have dropped 15 degrees so it would have been colder

Step-by-step explanation:

7 0

3 years ago