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skad [1K]
3 years ago
8

If h(x) = 6 - X, what is the value of (h.n)(10)? -2 10 16 Help pls

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
3 0

Answer:

16

Step-by-step explanation:

h(x) = 6 - X

Let x = -10

h(-10) = 6- -10

        = 6+ 10

        = 16

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Help please! If anyone knows
kiruha [24]
Just substitute the x for each of the values and do the work
8 0
3 years ago
there are 45 new houses built. Last month 2/3 of them sold. This month, 1/5 of the remaining houses were sold. How many houses l
Nady [450]

Answer: 9

Step-by-step explanation: 45 times 2/3 is 30. So, 30 houses were sold last month. 30 times 1/5 is 6. So, 6 houses were sold this month. Add them together. 30+6=36. Subtract that from 45 and you will get 9. There are 9 houses left to be sold.

7 0
3 years ago
X − 6 = 63 − 10(x + 8)
il63 [147K]

\red { \green {\boxed {\boxed{Answer}}}}

x - 6 =63 - 10(x + 8)

x - 6 = 63 - 10x - 80

x - 6 = 63 - 80 - 10x

x - 6 =  - 17 - 10x

x - 6  + 10x =  - 17

x + 10 x- 6 =  - 17

11x - 6 =  - 17

11x =  - 17 + 6

11x =  - 11

x =   \frac{ - 11}{11}

x =  - 1

#IfWrongPleaseReport

#StudyTogetherWithMe

#ILoveMath

8 0
3 years ago
Read 2 more answers
Suppose that there are 15 antennas in a store, of which 3 are defective. Assume all the defectives and all the functional antenn
ohaa [14]

Answer:

Step-by-step explanation:

Total number of antenna is 15

Defective antenna is 3

The functional antenna is 15-3=12.

Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.

So,

We line up the 13 good ones, and see where the bad one will fits in

__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __

Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.

Then,

There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement

ⁿCr= n!/(n-r)!r!

The number of arrangement is

14C3=14!/(14-3)!3!

14C3=14×13×12×11!/11!×3×2

14C3=14×13×12/6

14C3=364ways

7 0
3 years ago
Please solve this question.
andre [41]
  • <em>Answer:</em>

<em>x = - 2</em>

<em>y = 5</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>2x + 9 = y</em>

<em>y = - 4x - 3</em>

<em> </em>

<em>equality</em>

<em>2x + 9 = - 4x - 3</em>

<em>2x + 4x = - 9 - 3</em>

<em>6x = - 12</em>

<em>x = - 12 : 6</em>

<em>x = - 2</em>

<em>replace x = - 2</em>

<em>2(-2) + 9 = y</em>

<em>- 4 + 9 = y</em>

<em>y = 5</em>

<em>Good luck !</em>

<em />

<em />

8 0
3 years ago
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