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LekaFEV [45]
3 years ago
9

Write 5x = 40 as a logarithmic function

Mathematics
1 answer:
tekilochka [14]3 years ago
7 0
Log (5) + log (x) = log (40)


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PLEASE HELP!!!!
saveliy_v [14]

Answer:

Hi there!

Your answers are:

1) 38^10

2) 20^3

Step-by-step explanation:

1) Theres a property that goes like this:

(x^m)^n = x^mn

When you do a power of a power, you multiply them together!

2) There's a property that looks like this:

x^ m / x^n = x^ m-n

When dividing exponents, subtract!

Hope this helps!

8 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
(-6,8); perpendicular to y = -3/2x -1
UNO [17]

Answer:

y =  \frac{2}{3} x + 12

Step-by-step explanation:

y =  -  \frac{3}{2} x - 1

The gradient of a line is the coefficient of x when the equation of the line is written in the form of y=mx+c.

Thus, gradient of given line=-  \frac{3}{2}.

The product of the gradients of perpendicular lines is -1.

(Gradient of line)(-3/2)= -1

Gradient of line

- 1 \div ( -  \frac{3}{2} ) \\  =  - 1( -  \frac{2}{3} )  \\  =  \frac{2}{3}

Substitute m=\frac{2}{3} into y=mx+c:

y =  \frac{2}{3} x + c

To find the value of c, substitute a pair of coordinates.

When x= -6, y= 8,

8 =  \frac{2}{3} ( - 6) + c \\  \\ 8 =  - 4 + c \\ c = 8 + 4 \\ c = 12

Thus, the equation of the line is y =  \frac{2}{3} x + 12.

7 0
3 years ago
Please help me !!! :))))
jonny [76]

Answer:

12.4 in

Step-by-step explanation:

I whish i can help :)

7 0
2 years ago
Read 2 more answers
Pablo and max's follows a flight pattern approximatley modled by the equation h(t)=-8t^2+16t+2 where h(t)is their rocket's heigh
kodGreya [7K]

Answer: 2.11 s

Step-by-step explanation:

Given

Equation of rockets height is given by

\Rightarrow h(t)=-8t^2+16+2

Height will be zero once the rocket lands on the ground

So, we can write

\Rightarrow h(t)=0\ \text{or}\ -8t^2+16t+2=0\\\Rightarrow 8t^2-16t-2=0\\\\\Rightarrow t=\dfrac{16\pm \sqrt{(-16)^2-4(8)(-2)}}{2\times 8}\\\\\Rightarrow t=\dfrac{16\pm \sqrt{320}}{16}\\\\\text{Neglecting negative value of t}\\\\\Rightarrow t=\dfrac{16+17.888}{16}=2.11\ s

7 0
2 years ago
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