Answer is: <span> 1.4 × 10-10 m
</span>pH = 9.85.
[H₃O⁺] = 10∧(-9.85).
[H₃O⁺] = 1.4·10⁻¹⁰ M.
pH (potential of
hydrogen) is a numeric scale used to specify the acidity or basicity <span>an aqueous solution.
</span>If pH is greater than
seven, solution is base and if pH is equal seven, solution is neutral and if pH of solution is less than seven, than is acidic.<span>
</span>
We are given with the equation 2H2O2 --> 02 + 2H2O . In an equation, the right-hand side contains the products while the left-hand side consists of the reactants or substrate. In this case, the enzyme used to enhance the rate of the process is catalase. The answer hence is <span>D. Catalase is an enzyme, O2 and H2O are products, and H2O2 is a substrate.</span>
Answer:
12 molecules of carbon dioxide
24 molecules of water
Explanation:
Given parameters:
Number of molecules of methane = 12 molecules
Unknown:
Number of molecules of carbon dioxide = ?
Number of molecules of water = ?
Solution:
The given amount of methane is the limiting reagent in this reaction. By this, we can ascertain the amount of products that will be formed and the extent of the reaction.
We first write the balanced chemical equation for this reaction;
CH₄ + 2O₂ → CO₂ + 2H₂O
From balanced equation;
1 mole of methane produced 1 mole of carbon dioxide
12 molecules of methane will produce 12 molecules of carbon dioxide
Also;
1 mole of methane produced 2 moles of water;
12 molecules of methane will produce (12 x 2)molecules = 24 molecules of water
Answer:
1) HCl contains the Cl^- which is a good nucleophile
2) 2-methyl-2- heptanol > 2-heptanol > 1-heptanol
3) see image attached
Explanation:
If the dehydration of alcohols is carried out using HCl, the chloride ion which is a good nucleophile will attack the substrate to yield an undesirable product.
The dehydration of alcohols is an E1 reaction. Recall that the ease of E1 reaction increases in the order 3°> 2°> 1°. Hence, 2-methyl-2- heptanol forms a tertiary carbocation intermediate during dehydration and has the greatest ease of dehydration.
The three products formed during the dehydration of 3,3-dimethyl-2-butanol are shown in the image attached. Two out of the three are formed by rearrangement reactions.