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2 years ago

PLEASE HELP WILL AMRK BRAINLIEST what is the atomic mass of Na3PO4?

Chemistry

2 answers:

Ira Lisetskai [31]2 years ago

4 0

Answer:

163.94

Explanation:

Na = 22.99 (3)

P = 30.97

O = 16.00 (4)

22.99(3) + 30.97 +16.00(4) = 163.94

Hope that helps

Amanda [17]2 years ago

4 0

163.94 g/mol
I think.. sorry if I’m wrong! Have a nice day :)

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2 years ago

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2 years ago

calculate the (m/v) of nacl of a solution made by diluting 25.0 ml of a 7.50 (m/v)% NaCl solution to a total volume of 75.00 ml

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Answer:

Explanation:

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2 years ago

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What is the isotope notation of the element that has an atomic number of 24 and a mass number of 52?

Fofino [41]

Answer:

Chromium

Explanation:

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2 years ago

At what temperature would 2.10moles of N2 gas have a pressure of 1.25atm and fill a 25.0 L tank

hodyreva [135]

Answer:

$\large \boxed{\text{-92 $^{\circ}$C}}$

Explanation:

We can use the Ideal Gas Law and solve for T.

pV = nRT

Data

p = 1.25 atm

V = 25.0 L

n = 2.10 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

Calculations

1. Temperature in kelvins

$\begin{array} {rcl}pV & = & nRT\\\text{1.25 atm} \times \text{25.0 L} & = & \rm\text{2.10 mol} \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times T\\31.25&=&0.09847T\text{ K}^{-1}\\T& = &\dfrac{31.25}{\text{0.098 47 K}^{-1}}\\\\& = &\text{181 K}\end{array}$

2. Temperature in degrees Celsius

$\begin{array} {rcl}T & = & (181 - 273.15) \, ^{\circ}\text{C}\\& = & -92 \, ^{\circ}\text{C}\\\end{array}\\\text{The temperature of the gas is $\large \boxed{\mathbf{-92 \, ^{\circ}}\textbf{C}}$}$

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2 years ago