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2 years ago

PLEASE HELP WILL AMRK BRAINLIEST what is the atomic mass of Na3PO4?

Chemistry

2 answers:

Ira Lisetskai [31]2 years ago

4 0

Answer:

163.94

Explanation:

Na = 22.99 (3)

P = 30.97

O = 16.00 (4)

22.99(3) + 30.97 +16.00(4) = 163.94

Hope that helps

Amanda [17]2 years ago

4 0

163.94 g/mol
I think.. sorry if I’m wrong! Have a nice day :)

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What does atomic mass on the periodic table represent?

neonofarm [45]

The atomic mass on the periodic table represents the sum of number of protons and number of neutrons.

Atomic mass = Number of protons + number of neutrons

Hope this helps!

6 0

3 years ago

Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise

USPshnik [31]

Answer:

t = 37.1 s

Explanation:

The equation for the reaction is given as;

2 N2O5(g) --> 4 NO2 + O2

Initial: 0.110 - -

change: -2x +4x +x

Final: 0.110 - 2x +4x +x

But final = 0.150atm;

0.110 - 2x + 4x + x = 0.150 atm

3x = 0.150 - 0.110

x = 0.0133 atm

Pressure in reactant side;

0.110 - 2x

0.110 - 2 (0.0133) = 0.0834 atm

The integral rate law expression is given as;

ln ( [A] / [Ao] ) = -kt

k = rate constant = 7.48*10^-3*s-1

ln (0.0834/0.11) = (7.48*10^-3) t

upon solving, t = 37.1 s

3 0

3 years ago

How is the periodic table arranged ( give two ways)

vlabodo [156]

Left side metals right side non metals. arrganged in groups (columns) and periods (rows), each group tells you amount of valence electrons

7 0

2 years ago

A 15.0-L rigid container was charged with 0.500 atm of kryp‑ ton gas and 1.50 atm of chlorine gas at 350.8C. The krypton and chl

Alecsey [184]

Answer: 32.94 g

Explanation: It's stoichiometry problem so balanced equation is required. The balanced equation is given below:

$Kr+2Cl_2\rightarrow KrCl_4$

From the balanced equation, krypton and chlorine react in 1:2 mol ratio. We will calculate the moles of each reactant gas using ideal gas law equation(PV = nRT) and then using mol ratio the limiting reactant is figured out that helps to calculate the amount of the product formed.

for Krypton, P = 0.500 atm and for chlorine, P = 1.50 atm

V = 15.0 L

T = 350.8 + 273 = 623.8 K

For krypton, $n=\frac{0.500*15.0}{0.0821*623.8}$

n = 0.146 moles

for chlorine, $n=\frac{1.50*15.0}{0.0821*623.8}$

n = 0.439

From the mole ratio, 1 mol of krypton reacts with 2 moles of chlorine. So 0.146 moles of krypton will react with 2 x 0.146 = 0.292 moles of chlorine.

Since 0.439 moles of chlorine are available, it is present in excess and hence the limiting reactant is krypton.

So, the amount of product formed is calculated from moles of krypton.

Molar mass of krypton tetrachloride is 225.61 gram per mol.

There is 1:1 mol ratio between krypton and krypton tetrachloride.

$0.146molKr(\frac{1molKrCl_4}{molKr})(\frac{225.61gKrCl_4}{1molKrCl_4})$

= 32.94 g of $KrCl_4$

So, 32.94 g of the product will form.

5 0

3 years ago

What mass of Calcium Bromide (below) is needed to make 0.500 L of

Reika [66]

55.36 is the mass of Calcium Bromide is needed to make 0.500 L of 0.554 M solution.

Explanation:

Data given:

mass of Ca $Br_{2}$ = ?

molarity of the calcium bromide solution = 0.554 M

Volume of the calcium bromide solution= 0.5 L

First the moles of calcium bromide is calculated as:

molarity = $\frac{number of moles}{volume in litres}$

number of moles = 0.554 x 0.5

number of moles = 0.277 moles of calcium bromide

atomic mass of calcium bromide = 199.89 grams/mole

mass = atomic mass x number of moles

mass of calcium bromide = 199.89 x 0.277

= 55.36 grams

mass of calcium bromide required is 55.36 grams to make solution of 0.554 M in a solution of 0.5 litres.

5 0

3 years ago