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3 years ago

Help me pleaseeeee!!!!!

Chemistry

1 answer:

astraxan [27]3 years ago

5 0

Examples of pure substances are tin, sulfur, diamond, water, pure sugar, table salt, and baking soda

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3CuCl2 + 2Al => 3Cu + 2AlCl3

Marrrta [24]

The reaction includes the single replacement reaction and redox

<h3>Further explanation</h3>

Single replacement : one element replaces another element in a compound

A + BC ⇒ AC + B

The oxidation-reduction reaction or abbreviated as Redox is a chemical reaction in which there is a change in oxidation number

3CuCl + 2Al => 3Cu + 2AlCl₃

1. Single replacement

Al replacing Cu in the CuCl compound

2. Redox reaction

3Cu²⁺ + 6e⁻⇒ 3Cu reduction(oxidation number from +2 to 0)

2Al⇒2Al³⁺+6e⁻ oxidation(oxidation number from 0 to +3)

8 0

3 years ago

If 2 molecules of one reactant combine with 3 molecules of another to produce 5 molecules of a product, then what is the represe

zhenek [66]

Answer:- $2A+3B\rightarrow 5C$

Explanations:- Let's say the first molecule is A and the second molecule is B and the product molecule is C.

From given information, 2 molecules of A react with 3 molecules of B to produce 5 molecules of C.

We write the reactants on left side and the product on right side and there is an arrow between them from reactants towards the products.

So, the reaction could be represented as:

$2A+3B\rightarrow 5C$

3 0

3 years ago

Which of th following is an example of how scientist might use a model?

Gemiola [76]

C. marbles placed inside hollow sphere

8 0

3 years ago

The vapor pressure of ethanol is 400. mmhg at 63.5°c. its molar heat of vaporization is 39.3 kj/mol. what is the vapor pressure

Vilka [71]

Answer: -

100 mm Hg

Explanation: -

P 1 =400 mm Hg

T 1 = 63.5 C + 273 = 336.5 K

T 2 = 34.9 C + 273 = 307.9 K

ΔHvap = 39.3 KJ/mol = 39.3 x 10³ J mol⁻¹

R = 8.314 J ⁻¹K mol⁻¹

Now using the Clausius Clapeyron equation

ln (P1 / P2) = ΔHvap / R x (1 / T2 - 1 / T1)

Plugging in the values

ln (400 mm/ P₂) = (39.3 x 10³ J mol⁻¹ / 8.314 J ⁻¹K mol⁻¹) x ( $\frac{1}{307.9 K}$ - $\frac{1}{336.5 K}$

= 1.38

P₂ = 100 mm Hg

6 0

4 years ago

What is the individual ions for ZnCO3

mamaluj [8]

<span>ZnCO3 is an inorganic compound and it contains two parts; one is cation(positive part of compound) whereas other is anion(negative part of compound). Here, </span> $Zn ^{+2}$ <span> is cation and </span> $CO3 ^{-2}$ is anion. Hope this helps.

5 0

4 years ago