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4 years ago

Which is bigger 2 miles or 3 kilogram

Mathematics

1 answer:

artcher [175]4 years ago

4 0

The answer would be 2 miles.

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Can someone help me out please I don’t get this

expeople1 [14]

I think the answer is three

i did 9x-1=-5x+41 and i got 3

8 0

3 years ago

Sammy opened a college savings account. She opened the account with $85, and then

MrMuchimi

Answer:

C. s= 85m + 45

Step-by-step explanation:

Given data

She opened the account with $85

and deposited $85

The equation that best models the relationship is

s= 85m + 45

Hence option C is correct

8 0

3 years ago

The table below represents a linear function f(x) and the equation represents a function g(x):

Goshia [24]

The slope of f is 10 because as x increases by 1, f(x) increases by 10.The slope of g is lesser at 5, because every time x increases it only increases by 5. By plugging in 1 and 2 to g(x), we can see that g(2)=11, which is 5 more than g(1)=6.

6 0

3 years ago

The diameter of a circle is 28 inches what is the circle's area?<br><br> use 3.14 for pi

jolli1 [7]

Answer:

615.75216....

Step-by-step explanation:

The formula is A = π * (ø/ 2)^2

A = Circle area

π = Pi = 3.14

ø = Circle diameter

A= 3.14 (28/2)^2

5 0

4 years ago

Read 2 more answers

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

4 years ago