Question

Find the 39th term of the arithmetic sequence that starts with 4 and has a common difference of 6.

Answer 1

Any arithmetic sequence can be expressed as:

a(n)=a+d(n-1), a=initial term, d=common difference, n=term number.

We are told that a=4 and d=6 so we have:

a(n)=4+6(n-1), so the 39th term is:

a(39)=4+6(38)

a(39)=4+228

a(39)=232