When considering similar triangles, we need congruent angles and proportional sides.
Hence
"Angles B and B' are congruent, and angles C and C' are congruent." is sufficient to prove similarity of two triangles.
"Segments AC and A'C' are congruent, and segments BC and B'C' are congruent." does not prove anything because we know nothing about the angles.
"Angle C=C', angle B=B', and segments BC and B'C' are congruent." would prove ABC is congruent to A'B'C' if and only if AB is congruent to A'B' (not just proportional).
"<span>Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent</span>" is not sufficient to prove similarity nor congruence because SSA is not generally sufficient.
To conclude, the first option is sufficient to prove similarity (AAA)
This is an equilateral triangle, which is a triangle that has 3 congruent/equal sides and 3 congruent angles.
To find "x", you can set the sides equal to each other because they are suppose to be the same length (you can just do two sides because all of the sides are the same)
[Side AB = Side BC]
4x - 10 = 3x + 2 Subtract 3x on both sides
x - 10 = 2 Add 10 on both sides
x = 12
[proof]
Side AB:
4x - 10 Plug in 12 for x
4(12) - 10 = 48 - 10 = 38
Side BC:
3x + 2 Plug in 12 for x
3(12) + 2 = 36 + 2 = 38
Side AC:
5x - 22 Plug in 12 for x
5(12) - 22 = 60 - 22 = 38
This is also an equilateral triangle (the tick marks show that the sides are the same)
A triangle is 180°. So the three angles add up to 180°.
Since this is an equilateral triangle, all the angles should be the same.
Each angle is 60°
[60° + 60° + 60° = 180° or you could have divided 180 by 3 = 60]
Now that you know each angle is 60°, you can do:
(2x - 4)° = 60°
2x - 4 = 60 Add 4 on both sides
2x = 64 Divide 2 on both sides
x = 32
I don’t really know what it is but you can cross out A, B, and F for sure.
Solve by back-calculating for the missing number . . . (58 - 7 - 14 + 3)/(5 × 2) = 4
Answer:
0
Step-by-step explanation:
