What’s the correct answer for this question?
1 answer:
You might be interested in
Answer:
1) B. $12
2) B. Rich burns 1 more calorie per minute than Katie
3) C. Jeffery walks 5 meters per minute slower than Fumi.
Step-by-step explanation:
1) earnings / hours = salary
salary = 24/2 = 60/5 = 96/8 = 12
salary = $12
2) The question describes Rich's graph to have the function of "y=8x." The graph shown that represents Katie's number of burned calories has the function of "y=7x." From that we can conclude Rich burns one more calorie per minute. See attached file for graph.
3) The question describes Fumi's graph to have the function of "y=85x." In order to find the function of Jeffrey's graph, we must use the two points provided from the graph. The point (10, 800) tells us that the point (1,80) would also fall on the line. From that, we can determine Jeffery's function to be "y=80x." 80 is 5 less than 85, so Fumi walks 5 meters per minute faster than Jeffery.
Answer:
68% of the rates are expected to be betwen 0.718 and 0.762
95% of the rates are expected to be betwen 0.696 and 0.784
99.7% of the rates are expected to be betwen 0.674 and 0.806
Step-by-step explanation:
Check for conditions
For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:
a) Independence : we assume that the random sample of 400 students each student is independent from the other.
b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.
c) np= 400*0.74= 296>10
n(1-p) = 400*(1-0.74)=104>10
So then we have all the conditions satisfied.
Solution to the problem
For this case we know that the distribution for the population proportion is given by:
So then:
The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).
68% of the rates are expected to be betwen 0.718 and 0.762
95% of the rates are expected to be betwen 0.696 and 0.784
99.7% of the rates are expected to be betwen 0.674 and 0.806