Question

Una bicicleta que circula a 18km/h y se detiene en 0.8 segundos. Calcular la aceleración.

Answer 1

The acceleration is $-6.25 m/s^2$.

Explanation:

The acceleration of an object is given by:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time taken for the velocity to change from u to v

For the bike in this problem, we have:

$u=18 km/h \cdot \frac{1000 m/km}{3600 s/h}=5 m/s$ is the initial velocity

v = 0 is the final velocity (the bike comes to a stop)

t = 0.8 s is the time interval

Substituting, we find the acceleration:

$a=\frac{0-5}{0.8}=-6.25 m/s^2$

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