Answer:
f = 1 m
Explanation:
The magnification of the lens is given by the formula:
where,
M = Magnification = 4
q = image distance = 5 m
p = object distance = ?
Therefore,
Now using thin lens formula:
<u>f = 1 m</u>
A ball is dropped out of a window and hits the ground at 14.5 m/s. How long did it take to fall to the ground?
1 answer:
Answer:
Explanation:
Use the one-dimensional equation:
which says that the final velocity of a falling object is equal to its initial velocity times the acceleration of gravity times the time it takes to fall. We have the final velocity, -14.5 (negative because its direction is down and down is negative), initial velocity is 0 (because it was held still by someone before it was dropped), and acceleration is -9.8 (negative again, because direction is down while acceleration increases). Filling in:
-14.5 = 0 - 9.8t and
-14.5 = -9.8t so
t = 1.5 seconds
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(a) The screen is 3.20m from the split.
(b) The closest minima for green, distance Δy = 0.45 cm.
When a wave hits a barrier or opening, numerous events are referred to as diffraction. It is described as the interference or bending of waves via an aperture or around the corners of an obstruction into the area that forms the geometric shadow of the obstruction or aperture.
(a)Equation of minima = sinθ = mλ/α
Given, m = 3, λ = 6.33X10⁻⁷, α = 0.00015
Putting the values in formula to get θ.
θ = sin⁻¹ ( ) = 0.01266 rad
triangle need to be drawn to find relationship between θ, y$ and L
tan(θ) = y/L where; y = 4.05 cm
L = y/tan(θ) = 3.20
Hence, the screen is 3.20m from the split.
(b) Find the closest minima for green
minima equation is sinθ = mλ/α where, m = 4 (minima with smallest distance)
sinθ = 4λ/α
θ = sin⁻¹ () = 0.01688 rad
Calculate L using
tanθ = y/L
L = 4.5 cm
From equation subtract y₃ from y:
4.50 cm - 4.05 cm = 0.45 cm
Hence, distance Δy = 0.45 cm.
Learn more about the Diffraction with the help of the given link:
#SPJ4
I understand that the question you are looking for is "Two lasers, one red (with wavelength 633.0 nm) and the other green (with wavelength 532.0 nm), are mounted behind a 0.150-mm slit. On the ot
Question
Two lasers, one red (with wavelength 633.0 nm) and the other green (with wavelength 532.0 nm), are mounted behind a 0.150-mm slit. On the other side of the slit is a white screen. When the red laser is turned on, it creates a diffraction pattern on the screen.
a. The distance y3,red from the center of the pattern to the location of the third diffraction minimum of the red laser is 4.05 cm. How far L is the screen from the slit? Express this distance L in meters to three significant figures.
b. With both lasers turned on, the screen shows two overlapping diffraction patterns. The central maxima of the two patterns are at the same position. What is the distance Δy between the third minimum in the diffraction pattern of the red laser (from Part A) and the nearest minimum in the diffraction pattern of the green laser?
Answer:
The distance the bungee cord that would be stretched 0.602 m, should be selected when pulled by a force of 380 N.
Explanation:
As from the given data
the length of the rope is given as l=30 m
the stretched length is given as l'=41m
the stretched length required is give as y=l'-l=41-30=11m
the mass is m=95 kg
the force is F=380 N
the gravitational acceleration is g=9.8 m/s2
The equation of k is given by equating the energy at the equilibrium point which is given as
Here
m=95 kg, g=9.8 m/s2, h=41 m, y=11 m so
Now the force is
or
So here F=380 N, k=630.92 N/m
So the distance is 0.602 m