4 years ago

If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

1 answer:

8 0

Note that (a+b)^2 = a^2 + 2ab + b^2. This is always true.

Let's re-write the given "<span>ab = 8 and a^2+b^2=16" as
a^2 + 2ab + b^2 = 16 + 2ab, or, equivalently, as
(a+b)^2 = 16 + 2(8) = 32.
This is the answer we wanted.
</span>
<span>

</span>

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