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meriva
3 years ago
15

If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

Mathematics
1 answer:
Paul [167]3 years ago
8 0
Note that (a+b)^2 = a^2 + 2ab + b^2.  This is always true.

Let's re-write the given "<span>ab = 8 and a^2+b^2=16" as
  a^2 + 2ab + b^2 = 16 + 2ab, or, equivalently, as 
       (a+b)^2          = 16 + 2(8) = 32. 
 This is the answer we wanted.
</span>
<span>


</span>
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3 years ago
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