If f(x)= 3x^2+1 and g(x)= 1-x, what is the value of (f-g)(2)?

Mathematics

1 answer:

enyata [817]3 years ago

3 0

Answer:

Step-by-step explanation:

note that (f - g) = f(x) - g(x)

f(x) - g(x) = 3x² + 1 - (1 - x) = 3x² + 1 - 1 + x = 3x² + x

To evaluate (f - g)(2) substitute x = 2 into f(x) - g(x)

(f - g)(2) = 3(2)² + 2 = (3 × 4) + 2 = 12 + 2 = 14

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H function is even, odd, or neither. b. g(x) = x² - 2 Is it odd or even

o-na [289]

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Given that,

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We have to find whether the above function is odd or even

If a function is: y = f(x)

If f(-x) = f(x), the function is even

If f(-x) = - f(x), the function is odd

Which is,

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