Answer:
I'm not going to lie to you I have no idea I just want my free answers lol
Answer:
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Step-by-step explanation:
Answer: V = 209.43951023...
Rounded: 209.44
The Indian Ocean is 270 times greater. I found this by directly dividing the standard notation forms of the numbers.
Answer:
a) ![S_{a}(t)=16Kg-0.16Kg*\frac{t}{min}](https://tex.z-dn.net/?f=S_%7Ba%7D%28t%29%3D16Kg-0.16Kg%2A%5Cfrac%7Bt%7D%7Bmin%7D)
b) ![S_{a}(20)=12.8Kg](https://tex.z-dn.net/?f=S_%7Ba%7D%2820%29%3D12.8Kg)
Step-by-step explanation:
It can be seen in the graph that the water velocity and solution velocity is the same, but the salt concentation will be lower
Water velocity ![V_{w} = 60\frac{L}{min}](https://tex.z-dn.net/?f=V_%7Bw%7D%20%3D%2060%5Cfrac%7BL%7D%7Bmin%7D)
Solution velocity ![V_{s} = 60\frac{L}{min}](https://tex.z-dn.net/?f=V_%7Bs%7D%20%3D%2060%5Cfrac%7BL%7D%7Bmin%7D)
Brine concentration = ![\frac{6,000L}{16Kg}=375\frac{L}{Kg}](https://tex.z-dn.net/?f=%5Cfrac%7B6%2C000L%7D%7B16Kg%7D%3D375%5Cfrac%7BL%7D%7BKg%7D)
a) Amount of salt as a funtion of time Sa(t)
![S_{a}(t)=16Kg-\frac{60Kg*L}{375L}*\frac{(t)}{min}=[tex]16Kg-0.16Kg*\frac{t}{min}](https://tex.z-dn.net/?f=S_%7Ba%7D%28t%29%3D16Kg-%5Cfrac%7B60Kg%2AL%7D%7B375L%7D%2A%5Cfrac%7B%28t%29%7D%7Bmin%7D%3D%5Btex%5D16Kg-0.16Kg%2A%5Cfrac%7Bt%7D%7Bmin%7D)
b) ![S_{a}(20)=16Kg-0.16\frac{Kg}{min}*(20min)=16Kg-3.2Kg=12.8Kg](https://tex.z-dn.net/?f=S_%7Ba%7D%2820%29%3D16Kg-0.16%5Cfrac%7BKg%7D%7Bmin%7D%2A%2820min%29%3D16Kg-3.2Kg%3D12.8Kg)
This value was to be expected since as the time passes the concentration will be lower due to the entrance to the pure water tank