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Ivenika [448]
4 years ago
7

What is 57.048 rounded to three significant figures?

Chemistry
1 answer:
AnnyKZ [126]4 years ago
4 0
57.0 is it rounded to three sig figs. You count three spaces then round from there, which would be the zero and you would round down because the four is there.
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For each set of values, calculate the missing variable using the ideal gas law.
allsm [11]

Answer:

1. n = 0.174mol

2. T= 26.8K

3. P = 1.02atm

4. V = 126.88L

Explanation:

1. P= 2.61atm

V = 1.69L

T = 36.1 °C = 36.1 + 273= 309.1K

R = 0.082atm.L/mol /K

n =?

n = PV / RT = (2.61x1.69)/(0.082x309.1)

n = 0.174mol

2. P = 302 kPa = 302000Pa

101325Pa = 1atm

302000Pa = 302000/101325 = 2.98atm

V = 2382 mL = 2.382L

T =?

n = 3.23 mol

R = 0.082atm.L/mol /K

T= PV /nR = (2.98x2.382)/(3.23x0.082) = 26.8K

3. P =?

V = 0.0250 m³ = 25L

T = 288K

n = 1.08mol

R = 0.082atm.L/mol /K

P = nRT/V = (1.08x0.082x288)/25 = 1.02atm

4. P = 782 torr

760Torr = 1 atm

782 torr = 782/760 = 1.03atm

V =?

T = 303K

n = 5.26 mol

R = 0.082atm.L/mol /K

V = nRT/P

V = (5.26x0.082x303)/1.03 = 126.88L

8 0
4 years ago
Sodium metal is sometimes used as a cooling agent in heat exchange units because of its relatively high molar heat capacity of 2
IgorC [24]

Answer:

The specific heat of sodium is 1,23J/g°C

Explanation:

Using the atomic weight of sodium (23g/mol) and the atomic weight definition, we have that each mole of the substance has 23 grams of sodium.

starting from this, we use the atomic weight of sodium to convert the units from J / mol ° C to J / g ° C

28,2 \frac{J}{mol C} x \frac{1mol}{23g} = 1,23 J/g C

4 0
3 years ago
What is the formula for hydrogen iodide trihydrate
Natali [406]

HI.3H2O. This is the answer

6 0
3 years ago
Whenever you see an ‘N’, ‘S’, or ‘P’ followed by a bunch of oxygens you know you have a
Leya [2.2K]
Hhhhhhhhhhhhhhhhhhhhh
4 0
3 years ago
Read 2 more answers
What volume of 0.500 M HNO3(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?
asambeis [7]
KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol HNO3= 1 mol KOH (keep in mind this because it will be used later).

We also know that 0.100 M KOH aqueous solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the definition of molarity).

First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/ 1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.

Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.

The final answer is </span>(2) 20.0 mL.<span>

Also, this problem can also be done by using dimensional analysis. 

Hope this would help~ </span>
6 0
3 years ago
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