Answer:
d = 0.793 g/L
Explanation:
Given data:
Density of fluorine gas = ?
Pressure of gas = 0.554 atm
Temperature of gas = 50 °C (50+273.15K = 323.15 K)
Solution:
Formula:
PM = dRT
M = molar mass of gas
P = pressure
R = general gas constant
T = temperature
d = PM/RT
d = 0.554 atm × 37.99 g/mol / 0.0821 atm.L /mol.K × 323.15 K
d = 21.05 atm.g/mol/26.53 atm.L /mol
d = 0.793 g/L
It forms Carbon monoxide.
CO2 +O2⇒ CO
(Sorry not balanced)
Answer:
C₆H₁₂O₆ (glucose)
A molecular substance.
Explanation:
C₆H₁₂O₆ does not dissociate. It is not a ionic type.
There is no metal in the compound, it is not a metallic type.
Glucose is an organic molecule, a type of carbohidrate, the most common from the monosaccharides type.
If a molecule has four hybrid sp3 orbitals, it can be concluded that the molecule has a TETRAHEDRAL GEOMETORY
<span>A </span>flexible container<span> at an </span>initial volume<span> of 7.14 </span>L contains<span> 7.51 </span>mol<span> of </span>gas<span>. </span>More gas<span> is</span>then added<span> to the </span>container until<span> it </span>reaches<span> a </span>final volume<span> of 17.7 </span>L<span>. </span>Assuming<span> the </span>pressure<span> and</span>temperature<span> of the </span>gas remain constant<span>, </span>calculate<span> the </span>number<span> of </span>moles<span> of </span>gas added<span> to the </span>container<span>.</span>
