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2 years ago

6

What is 5/8 in decimals?

2 answers:

Gnoma [55]2 years ago

8 0

0.658 is the answer

hope this helps :)

Charra [1.4K]2 years ago

7 0

You divide 5/8.
5/8 = 0.625.

0.625 is the decimal form of 5/8.

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If you roll six sided dice what are the odds of rolling doubles

Ludmilka [50]

Answer: 16.7%

There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice. So you have a 16.7% probability of rolling doubles with 2 fair six-sided dice.

Second Answer : 6/36

Out of the 6^2 = 36 outcomes, there is only 6 that are doubles (double 1,double 2,… double 6). Therefore the probability is 6/36 i 1/6.

5 0

3 years ago

It has long been reported that human body temperature follows a normal distribution with a mean of 98.6 degrees Fahrenheit. Ther

Kay [80]

Solution :

The normal body temperature of any human body is considered to be 98.6 $^\circ \ F$ . But there is a constant debate about the body temperature of a long held standard to the body temperature.

It is given that :

Null hypothesis and alternate hypothesis :

$H_0 : \mu = 98.6$

And $H_A : \mu > 98.6$

n is given as = 180

Test statistics = 3.64

Prove = 0.018 < α = 0.05 (let reject null hypothesis for α = 0.05 )

Therefore, their results are statistically significant and the result is unlikely due to chance alone.

7 0

2 years ago

How to answer this question

12345 [234]

Flip the fraction to make the -3 exponet positive then it will be 9x^5/3x^3 which the answer would then be 3x^2

7 0

2 years ago

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Bobbi wanted to purchase a shirt that had an original price of $38.99 at the store where she works. She gets an employee discoun

uranmaximum [27]

C
38.99x0.25=9.7475
38.99-9.7475=29.2425

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2 years ago

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In a group of equal number of men and women 10% men and 45% women are suffering from Malaria.What is probability a peraon select

Kaylis [27]

Answer:

The probability a person selected random is not suffering from Malaria is 0.725.

Step-by-step explanation:

Denote the events as follows:

X = a person is suffering from Malaria

M = a man

W = a woman

The information provided is:

P (M) = P (W) = 0.50

P (X|M) = 0.10

P (X|W) = 0.45

Compute the probability a person selected random is suffering from Malaria as follows:

$P(X)=P(X|M)P(M)+P(X|W)P(W)$

$=(0.10\times 0.50)+(0.45\times 0.50)\\\\=0.05+0.225\\\\=0.275$

Then the probability a person selected random is not suffering from Malaria is:

P (X') = 1 - P (X)

= 1 - 0.275

= 0.725

4 0

2 years ago