6 m/s
This type of collision is a <u>Inelastic collision </u>
Explanation:
We begin by finding the momentum of the initial train car;
Remember that momentum is given by the formulae mass (kg) * velocity (m/s)
Therefore;
Momentum = 6000 * 10
= 60,000 kg⋅m/s
The other car has zero momentum because;
4000 * 0
= 0
When the two train cars collide, the total momentum will be;
60,000 + 0 = 60,000
Therefore to find the velocity, well use the same formulae;
p = mv whereby;
p – momentum
m – mass
v – velocity
60,000 = (6000 + 4000) * v
v = 60,000 / 10,000
v = 6
= 6 m/s
This is an elastic collision because we are assuming that no energy is lost in the collision. Most collisions, however, are not elastic but rather inelastic. In inelastic collision some of the kinetic energy is lost to the environment in some other form of energy such as heat energy.
Learn More:
For more on elastic collisions check out;
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Answer:
m1*v1 = m2 v2
1200kgm/s=600kg*v1=(7+600)*v2
6000=607*v
v2=9.8m/s
Explanation:
its need velocity
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