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kakasveta [241]
3 years ago
14

A 100-gram sample of a radioactive isotope decays at a rate of 6% every week. How much of the sample will be left one year from

now?
Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

4 grams sample will be left after 1 year

Step-by-step explanation:

The decay function for percentage decay is given by:

y =a (1-r)^x

Here,

a is the initial value

r is the rate

x is the number of time periods

Given

Initial value = 100 grams

Rate = 6% = 0.06

Time = 1 year = 52 weeks

Putting the values in the formula

y = 100 (1-0.06)^{52}\\y = 100(0.94)^{52}\\y = 4.00\ grams

Hence,

4 grams sample will be left after 1 year

Keywords: Decay, percentage

Learn more about decay functions at:

  • brainly.com/question/103144
  • brainly.com/question/10382470

#LearnwithBrainly

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Find all solutions of the equation in the interval [0,2π) sec(theta) +2=0
Komok [63]
I will first reveal the most obvious secret of trig: Most of the problems are 30/60/90 or 45/45/90 triangles of some sort.

\sec \theta + 2  = 0

\dfrac{1 }{ \cos \theta} = -2

\cos \theta = - \frac 1 2

The rule to remember is \cos x = \cos a has solutions

x = \pm a + 2 \pi k \quad integer k

Continuing where we left off, a cosine of -1/2 is a 30/60/90 triangle in the second or third quadrant; we pick second, and a little thought tells us the angle is  120^\circ.

\cos \theta = - \frac 1 2

\cos \theta = \cos \frac {2\pi} 3

\theta = \pm \frac {2\pi} 3 + 2 \pi k \quad integer k

In the range we want, that's k=0 with the plus sign and k=1 with the minus, so 

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6 0
3 years ago
Solve the following equation <br> 2/7x + 2 =<br> 6
Oksi-84 [34.3K]

Answer:

x=1/14

Step-by-step explanation:

2/7x+2=6

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2+14x=42x

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3 0
3 years ago
3. Given: BAM is a right angle. If mBAM=4x+2, then solve for the value of x.
Dafna11 [192]

Answer:

3. x = 17

4. a. m<NMP = 48°

b. m<NMP = 60°

Step-by-step explanation:

3. Given that <BAM = right angle, and

m<BAM = 4x + 22, set 90° equal to 4x + 22 to find x.

4x + 22 = 90

Subtract 22 from both sides

4x + 22 - 22 = 90 - 22

4x = 68

Divide both sides by 4

4x/4 = 68/4

x = 17

4. a. m<NMQ = right angle (given)

m<PMQ = 42° (given)

m<PMQ + m<NMP = m<NMQ (angle addition postulate)

42 + m<NMP = 90 (substitution)

m<NMP = 90 - 42 (subtracting 42 from each side)

m<NMP = 48°

b. m<NMQ = right angle (given)

m<NMP = 2*m<PMQ

Let m<PMQ = x

m<NMP = 2*x = 2x

2x + x = 90° (Angle addition postulate)

3x = 90

x = 30 (dividing both sides by 3)

m<PMQ = x = 30°

m<NMP = 2*m<PMQ = 2*30

m<NMP = 60°

4 0
3 years ago
What is the solution to this system of linear equations 2x+y=1 and 3x-y=-6
nikklg [1K]
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---------------add
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3 years ago
What is the value of F in the formula F=9/5C+32 when C=30?
kherson [118]
I don't know i think is C
8 0
3 years ago
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