Atomic Theory is

Chemistry

1 answer:

svetlana [45]3 years ago

7 0

It is A. subject to change if new information is discovered

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Help sdfghrthfbfdve aahhhhhhhh

nirvana33 [79]

I believe the answer is C !

5 0

3 years ago

Identify whether each compound is a straight chain, branched chain, or cycloalkane,

Delvig [45]

Answer:

First Part: branched chain, cycloalkane, straight chain

Second Part: straight chain, branched chain, cycloalkane.

Explanation:

Edg 2021

7 0

3 years ago

If you react 156.0 g of calcium chloride with an excess NaOH, how much sodium chloride should you get?

laiz [17]

Answer:

164.3g of NaCl

Explanation:

Based on the chemical equation:

CaCl2 + 2NaOH → 2NaCl + Ca(OH)2

where 1 mole of CaCl2 reacts with 2 moles of NaOH

To solve this question we must convert the mass of CaCl2 to moles. Using the chemical equation we can find the moles of NaCl and its mass:

Moles CaCl2 -Molar mass: 110.98g/mol-

156.0g CaCl₂ * (1mol / 110.98g) = 1.4057 moles CaCl2

Moles NaCl:

1.4057 moles CaCl2 * (2mol NaCl / 1mol CaCl2) = 2.811 moles NaCl

Mass NaCl -Molar mass: 58.44g/mol-

2.811 moles NaCl * (58.44g / mol) = 164.3g of NaCl

7 0

3 years ago

In a 1.0-liter container there are, at equilibrium, 0.10 mole h2, 0.20 mole n2, and 0.40 mole nh3. what is the value of kc for t

bogdanovich [222]

The reaction involved here would be written as:

2N2 + 3H2 = 2NH3

The equilibrium constant of a reaction is the ratio of the concentrations of the products and the reactants when in equilibrium. The expression for the equilibrium constant of this reaction would be as follows:

Kc = [NH3]^2 / [N2]^2[H2]^3
Kc = 0.40^2 / (0.20)^2 (0.10)^3
Kc = 4000

6 0

3 years ago

2. Balance the equation below, and answer the following question: What volume of chlorine gas, measured at STP, is needed to com

Juliette [100K]

Balanced equation: 2Na(s) + Cl₂(g) ---> 2NaCl(s)

when we have STP conditions, we can use this conversion: 1 mol = 22.4 L

first, we have to convert grams to molecules using the molar mass, and then use mole to mole ratio from the balanced equation.

molar mass of Na= 23.0 g/mol
ratio: 2 mol Na= 1 mol Cl₂ (based on coefficients of balanced equation)

calculations:

$6.25 g Na ( \frac{1 mol Na}{23.0 g} ) ( \frac{1 mol Cl_2}{2 mol Na} ) ( \frac{22.4 L}{1 mol} )= 3.04 L$

8 0

3 years ago