Answer:
The concentration of H⁺ in stomach acid is approximately ten times greater than that of lemon juice.
Explanation:
The H⁺ concentration of a solution is exponentially related to its pH value:
![\rm [H^{+}] = 10^{-pH}](https://tex.z-dn.net/?f=%5Crm%20%5BH%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-pH%7D)
.
For lemon juice:
![\rm [H^{+}] = 10^{-2.0} = 0.01\; M](https://tex.z-dn.net/?f=%5Crm%20%5BH%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-2.0%7D%20%3D%200.01%5C%3B%20M)
.
For stomach acid:
![\rm [H^{+}] = 10^{-1.0} = 0.1\; M](https://tex.z-dn.net/?f=%5Crm%20%5BH%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-1.0%7D%20%3D%200.1%5C%3B%20M)
.
Thus, the concentration of H⁺ in stomach acid is approximately ten times greater than that of lemon juice.
Answer:
Explanation:
There are three types of interactions involved between the particles when solution are formed.
1 : Solute - solute interaction:
2 : Solute - solvent interaction:
3 : Solvent - solvent interaction:
1 : Solute - solute interaction:
It is the inter-molecular attraction between the solute particles.
2 : Solute - solvent interaction:
It involve the inter-molecular attraction between solvent and solute particles.
3 : Solvent - solvent interaction:
It involve the intermolecular attraction between solvent particles.
Solutions are formed if the intermolecular attraction between solute particles are similar to the attraction between solvent particles.
Exothermic process:
The process will exothermic when solute solvent bonds are formed with the release of energy and energy required to brake the solute-solute particles and solvent solvent particles are less.
Endothermic process:
The process will be endothermic when energy required to break the solute-solute particles and solvent solvent particles are higher than energy released when solute solvent bonds are formed .
<span>equilibrium constant times the concentration of water. - 100% guaranteed correct</span>
Answer:
Explanation:
Hello.
In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:
Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:
Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:
Best regards!
2 is the number as you need to balance the equation
