Answer:
a−4b
Step-by-step explanation:
Combine Like Terms:
=4a+−6b+−3a+2b
=(4a+−3a)+(−6b+2b)
=a+−4b
have a great day
Answer:
Cos θ = -4/5
Tan θ = -3/4
Step-by-step explanation:
The question is as following:
Select the correct answer from each drop-down menu.
Angle θ lies in the second quadrant, and sin θ =3/5.
cos θ = -4/5, -3/5, 3/5, 4/5
tan θ = -4/3, -3/4, 3/4, 4/3
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Since, the angle lies in second quadrant (negative x axis and positive y axis) we can deduce that cos θ is negative and tan θ is also negative.
If sin θ =3/5

∴ Cos θ = -4/5 ⇒ because θ lies in the second quadrant.
And
Tan θ = (sin θ)/(cos θ) = (3/5) / (-4/5) = -3/4.
Answer:
x=2
x=-5
Step-by-step explanation:
You need to get everything on one side to have a quadratic equation:
x^2+6x-4 -(3x+6) = x^2+3x-10
All factors of 10 are 1*10 and 2*5.
5-2 = 3 and 5*-2 = -10
Factoring x^2+3x-10 gives us (x-2)(x+5)
x=2
x=-5
Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15
so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields
thus

solve for "x"
what's "y"? well, y = 100 - x
<h3>
Answer:</h3>
Any 1 of the following transformations will work. There are others that are also possible.
- translation up 4 units, followed by rotation CCW by 90°.
- rotation CCW by 90°, followed by translation left 4 units.
- rotation CCW 90° about the center (-2, -2).
<h3>
Step-by-step explanation:</h3>
The order of vertices ABC is clockwise, as is the order of vertices A'B'C'. Thus, if reflection is involved, there are two (or some other even number of) reflections.
The orientation of line CA is to the east. The orientation of line C'A' is to the north, so the figure has been rotated 90° CCW. In general, such rotation can be accomplished by a single transformation about a suitably chosen center. Here, we're told there is <em>a sequence of transformations</em> involved, so a single rotation is probably not of interest.
If we rotate the figure 90° CCW, we find it ends up 4 units east of the final position. So, one possible transformation is 90° CCW + translation left 4 units.
If we rotate the final figure 90° CW, we find it ends up 4 units north of the starting position. So, another possible transformation is translation up 4 units + rotation 90° CCW.
Of course, rotation 90° CCW in either case is the same as rotation 270° CW.
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We have described transformations that will work. What we don't know is what is in your drop-down menu lists. There are many other transformations that will also work, so guessing the one you have available is difficult.