What does x equal? 81x−122=22

2 answers:

5 0

81x - 122 = 22

We're simply just trying to isolate "x." This basically just means that we want to get "x" onto its own side of the equal sign :)

So, in order to do that, we need to get everything that does not have "x" in it onto the right side.

So, our first step is to add 122 to both sides.

81x - 122 + 122 = 22 + 122

Simplify.

81x = 144

Now, divide both sides by 81.

81x ÷ 81 = 144 ÷ 81

Simplify.

x = 144/81

Simplify this by dividing 144 and 81 by 9.

144 ÷ 9 = 16
81 ÷ 9 = 9

So, x = 16/9

~Hope I helped!~

Sliva [168]2 years ago

4 0

Hi there!
81x - 122 = 22
Add 122 to both sides
81x = 144
Divide 81 from both sides
x = 144/81
Simplify
x = 16/9 or 1.78
Hope this helped!

You might be interested in

3m + 5 = 8 modeled by algebra tiles

Lesechka [4]

3m+5=8
subtract 5 from both sides
3m=3
divide both sides by 3
m=1

I hope I helped! :)

4 0

2 years ago

Read 2 more answers

How does the graph of f(x)=3lx+2l+4 relate to its parent function?

Sergeeva-Olga [200]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units

check the picture below