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4 years ago

Calculati masa de CuSO4 necesare pentru a prepara 2 litiri de solutie 2M HELP!

Chemistry

1 answer:

LenaWriter [7]4 years ago

3 0

Calculate mass of CuSO4 needed to prepare 2 lithium l of 2M solution :D

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Answer:

540

Explanation:

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3 years ago

What is the definition of the following word sublimitation

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the transition of a substance directly from the solid to the gas phase, without passing through the intermediate liquid phase.

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3 years ago

The mass of a solid substance is 21.1164 g. If the volume of

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Answer:

The density of the substance is 1.0611 $\frac{g}{cm^{3} }$

Explanation:

The density of a substance is a characteristic property that matter, whether solids, liquids or gases, has to be compressed in a given space, that is, it allows us to measure the amount of mass in a certain volume of a substance.

Density is expressed as follows:

$density=\frac{mass}{volume}$

In this case:

density: ?
mass: 21.1164 grams
volume: 19.9 cm³

Replacing:

$density=\frac{21.1164 grams}{19.9 cm^{3} }$

density= 1.0611 $\frac{g}{cm^{3} }$

The density of the substance is 1.0611 $\frac{g}{cm^{3} }$

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4 years ago

Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3 ( is ) . The equation for the

anyanavicka [17]

Answer:

The answer to your question is 52.35 g of O₂

Explanation:

mass of oxygen = ?

mass of KClO₃ = 66.8 g

Chemical balanced reaction

KClO₃ ⇒ 2 KCl + 3O₂

Process

1.- Calculate the molar mass of KClO₃ and Oxygen

KClO₃ = 39 + 35.5 + (16 x 3) = 122.5 g

O₂ = 16 x 6 = 96 g

2.- Write proportions to solve this problem

122.5 g of KClO₃ ----------------- 96 g of O₂

66.8 g ----------------- x

x = (66.8 x 96) / 122.5

x = 6412.8/122.5

x = 52.35 g of O₂

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4 years ago