Answer:
1) Moles of CO 2 = Given mass / Molecular mass of CO 2 = 4.4 / 44 = 0.1 mole. 2) Molecules of CO2 in 0.1 moles of CO2 = 0.1 x 6.023 x 10 23 = 6.023 x 10 22 molecules 3) 44 gram (molecular wt of CO 2) contains 2 moles atom of oxygen therefore 4.4 gram of CO2 will contain = 2 /44 *4.4 = 0.2 moles atom of Oxygen.
<u>Answer:</u> The final volume of the reaction is 4.69 L
<u>Explanation:</u>
The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.
The equation used to calculate number of moles is given by:
where,
are the initial volume and number of moles
are the final volume and number of moles
We are given:
Putting values in above equation, we get:
Hence, the final volume of the reaction is 4.69 L
Sandblasted: More smooth because all the rough edges are "blasted" away. And slightly smaller because of the loss of the edges.
Non-Sandblasted: Not smooth; rough.
Answer:
0.089
Explanation:
2.5/ 14= .178 then 0.178/ 2 again and you get 0.089