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3 years ago

What are two observations you made from viewing the solar system model?

Chemistry

1 answer:

oksian1 [2.3K]3 years ago

3 0

Answer:

The two observations we made from viewing the solar system model are as follows as:

1). When we look at the sky we observe that the motions of all the planets and the stars are perfect circular movements with a good and high speed, but not in velocity because in velocity direction doesn't charges.

2). The sun is at the centre of our solar system and all the planets are equidistant to each other planets and also revolve around the sun.

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A certain hydrocarbon has a molecular formula of C9H16. Which of the following is not a structural possibility for this hydrocar

snow_tiger [21]

Answer: Option (d) is the correct answer.

Explanation:

It is given that molecular formula is $C_{9}H_{16}$ . Now, we will calculate the degree of unsaturation as follows.

Degree of unsaturation = $C_{n} - \frac{\text{monovalent}}{2} + \frac{\text{trivalent}}{2} + 1$

= $9 - \frac{16}{2} + 1$

= 9 - 8 + 1

= 2

As the degree of unsaturation comes out to be 2. It means that this compound will contain one ring and one double bond.

Yes, this compound could be an alkyne as for alkyne D.B.E = 2.

But this compound cannot be a cycloalkane because for a cycloalkane D.B.E = 1 which is due to the ring only.

Thus, we can conclude that it is a cycloalkane is not a structural possibility for this hydrocarbon.

6 0

4 years ago

AYUDENME A CONTESTAR ESTO

Zigmanuir [339]

umm how do you begin answering that ??

8 0

3 years ago

How many grams of nitrogen are needed to produce 812 grams of ammonia?

viva [34]

Is this multi choice or no?

8 0

3 years ago

Explain How does its structure affect its function

Slav-nsk [51]

Answer:

What are we talking about here?

Explanation:

3 0

3 years ago

How many particles of Na are there in 1.43g of a molecular compound with a Molar mass of 23g?

Olin [163]

Answer:

3.74 x 10²² particles

Explanation:

Given parameters:

Mass of compound = 1.43g

Molar mass of compound = 23g

Unknown:

Number of particles of sodium = ?

Solution:

To find the number of particles of Na in the compound, we need to obtain the mass of sodium from the total mass given;

Mass of sodium = $\frac{molar mass of Na}{molar mass of compound} x mass of sample$

= $\frac{23}{23} x 1.43g$

= 1.43g

Now find the number of moles of this amount of Na in the sample;

Number of moles = $\frac{mass}{molar mass}$ = $\frac{1.43}{23}$ = 0.062mole

Now;

1 mole of substance = 6.02 x 10²³ particles

0.062 mole of substance = 0.062 x 6.02 x 10²³ particles

= 3.74 x 10²² particles

7 0

3 years ago