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nata0808 [166]
3 years ago
5

I’ve been stuck in this question. Please help me.

Mathematics
2 answers:
strojnjashka [21]3 years ago
6 0

Answer:

They are congruent triangle

Step-by-step explanation:

They are congruent because they have the same measurements for angles and sides.

Veronika [31]3 years ago
5 0
D. They are congruent triangles


School sucks doesn’t it?
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Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
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Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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