The value of maximum velocity will be 0.3464 m/s². Energy or work is equal to the product of force and displacement.
<h3>What is velocity?</h3>
The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
Mass of the body is,(m= 200g)
Amplitude is,(A =20 mm)
Maximum force is,F= 0.6 N
To find;
Maximum velocity
Energy or work is equal to the product of force and displacement.
Hence,the value of maximum velocity will be 0.3464 m/s².
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Answer:
Explanation:
DetaM=4 x 1.02875 - 4.002603
DetaM= 0.028697u
Using E= mc²
= 0.028697 x 1.49x*10^-10
= 4.2x10^-12J
Answer:
4.42 x 10⁷ W/m²
Explanation:
A = energy absorbed = 500 J
η = efficiency = 0.90
E = Total energy
Total energy is given as
E = A/η
E = 500/0.90
E = 555.55 J
t = time = 4.00 s
Power of the beam is given as
P = E /t
P = 555.55/4.00
P = 138.88 Watt
d = diameter of the circular spot = 2.00 mm = 2 x 10⁻³ m
Area of the circular spot is given as
A = (0.25) πd²
A = (0.25) (3.14) (2 x 10⁻³)²
A = 3.14 x 10⁻⁶ m²
Intensity of the beam is given as
I = P /A
I = 138.88 / (3.14 x 10⁻⁶)
I = 4.42 x 10⁷ W/m²
Answer:
Acceleration = 9 × 10^5 m/s^2 ( deceleration )
Explanation:
From the first equation of motion:
V = u + at
15000 = 30000 + 60a
a = ( 15000-30000)/60
a = 9 × 10^5 m/s^2
