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Taya2010 [7]
3 years ago
5

A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static f

riction acting on the box if box has a gravitational force of 112.1 N ?
Physics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

Explanation:

The force of static friction acting on the box is the frictional force;

Frictional force Ff = Wsin theta (force acting along the ramp)

W is the gravitational force known as the weight

Ff = 112.1sin42°

Ff = 112.1(0.6691)

Ff = 75.00N

Hence he force of static friction acting on the box  if box has a gravitational force of 112.1 N id 75.00N

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