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kondaur [170]
4 years ago
5

The strong nuclear force is

Physics
1 answer:
katrin2010 [14]4 years ago
4 0

The force that holds the nucleus of the atom together even though other forces want to pull it apart.

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Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano.
Nonamiya [84]

Answer:

gravitational force acting on the piano (piano's weight)

force of Chadwick on the piano

force of the floor on the piano (normal force)

Explanation:

Figure is missing: found it in attachment.

In the figure, we notice that the piano is accelerating along the horizontal direction: this means that there is a net force acting along this direction. This force is prodiced by Chadwick, and it acts in the same direction as the acceleration, so one force is:

force of Chadwick on the piano

Also, every object on Earth experencies the force of gravity, which is also called weight. The weight of the piano acts downward, so a second force is:

gravitational force acting on the piano (piano's weight)

Finally, we notice that the piano is in equilibrium along the vertical direction (no acceleration): this is because there is another force acting opposite to the piano's weight (and with equal magnitude), and this force is the normal force exerted by the floor on the piano:

force of the floor on the piano (normal force)

3 0
3 years ago
PLEASE HELP ASAP
otez555 [7]

Answer:

D: unconscious

Explanation:

Apex have a nice day :)

7 0
4 years ago
How much KCI can be dissolved in 100 g of water at 30°C?​
asambeis [7]

Answer:

34

Explanation:

The problem provides you with thesolubility of potassium chloride, KCl , in water at 20∘C , which is said to be equal to 34 g / 100 g H2O . This means that at 20∘C , a saturated solution of potassium chloride will contain 34 g of dissolved salt for every100 g of water.

6 0
3 years ago
Read 2 more answers
An object has a net charge of +5 Coulombs.
exis [7]
The net charge of the electron will be there because there is no exponents there
3 0
3 years ago
A horse 1 m tall running towards a tree at a constant velocity of 20m/s,
kykrilka [37]

The horse's position on the ground at time <em>t</em> is

<em>x</em> = (20 m/s) <em>t</em>

The baboon's height from the ground at time <em>t</em> is

<em>y</em> = 3 m - 1/2 <em>g</em> <em>t</em>²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.

The baboon falls and lands on the horse, so that the two animals meet when the baboon's height is 2 m from the ground, which happens after

2 m = 3 m - 1/2 <em>g</em> <em>t</em>²

1/2 <em>g</em> <em>t</em>² = 1 m

<em>t</em>² = (2 m) / (9.80 m/s²)

<em>t</em> ≈ 0.452 s

In this time, the horse reaches the tree, so its distance from it is

(20 m/s) * (0.452 s) ≈ 9.04 m

7 0
4 years ago
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