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4 years ago

When written in standard form, which polynomial has a leading coefficient of 5?

1 answer:

8 0

Choice A

The polynomial for choice A can be written as 5y^2+6y+3. The leading term is 5y^2. The coefficient for this term is 5, so the leading coefficient is 5

So Choice A is one of the answers. It turns out that choice A is the only answer (see below)

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Choice B

The leading coefficient for x+3 is 1
This is because x+3 is the same as 1x+3
We can rule out choice B since the leading coefficient is not 5

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Choice C

Rearrange the terms in x^2-3x^3+2x to get -3x^3+x^2+2x
The leading coefficient is -3
We can rule out choice C

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Choice D

The leading coefficient here is 3 because the standard form is 3y^2+5y-4
We can rule out choice D

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Summary: The only answer is choice A

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Using the law of sines:

$\frac{b}{sin(B)}=\frac{c}{sin(C)}$

Solve for b:

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Step-by-step explanation:

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4 years ago

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4 years ago

A table of values of a linear function is shown below.

STALIN [3.7K]

Answer:

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Step-by-step explanation:

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3 years ago

A poker hand consisting of 7 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

77julia77 [94]

Answer:

The probability is 2,010,580/13,378,456

Step-by-step explanation:

Here is a combination problem.

We want to 7 cards from a total of 52.

The number of ways to do this is 52C7 ways.

Also, we know there are 12 face cards in a standard deck of cards.

So we are selecting 3 face cards from this total of 12.

So also the number of cards which are not face cards are 52-12 = 40 cards

Out of all these 40, we shall be selecting exactly 4. The number of ways to do this 40C4

Thus, the required probability will be;

(40C4 * 12C3)/52C7 = (91,390 * 220)/133,784,560

= 20,105,800/133,784,560 = 2,010,580/13,378,456

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4 years ago