The answer is table D as it is the only one without a repeated input ❤️ hope that helps
6x^3y^9/36x^3y^-2 The x^3 values cancel each other out leaving the 1/6
(1/6)y^9/(y^-2) the y^-2 causes the y^9 to turn into y^11 (9+2=11)
(1/6)y^11/1 the 1/6 is multiplied by y^11
y^11/6
Find the first semicircle area
Area semicircle can be determined by dividing the full area of circle by 2.
The first semicircle radius is 5 cm
semicircle area = 1/2 circle area
semicircle area = 1/2 × π × r²
semicircle area = 1/2 × 3.14 × 5²
semicircle area = 1/2 × 3.14 × 25
semicircle area = 39.25 cm²
Find the second semicircle area
Because the dimension of the second semicircle is congruent to the first semicircle, they have similar area measurement, 39.25 cm².
Find the quarter circle area
The area of quarter circle can be determined by dividing the full area of a circle by 4.
q circle = 1/4 × area of circle
q circle = 1/4 × π × r²
q circle = 1/4 × 3.14 × 10²
q circle = 1/4 × 314
q circle = 78.5 cm²
To find the entire area, add the area above together
area = first semicircle + second semicircle + q circle
area = 39.25 + 39.25 + 78.5
area = 157
The area of shaded region is 157 cm²
Answer:
8
Step-by-step explanation:
41-9=32
32/4=8
Answer:
Division
Step-by-step explanation:
PEMDAS
Parenthesis
Exponents
Multiplecation
Division
Addition
Subtraction
You have both exponents and parenthesis, so your third step would be multiplecation, but you don't have that, so it would be division.
