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Answer:
1.30464 grams of glucose was present in 100.0 mL of final solution.
Explanation:
Moles of glucose = 
Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)
Molarity of the solution = 
A 30.0 mL sample of above glucose solution was diluted to 0.500 L:
Molarity of the solution before dilution = 
Volume of the solution taken = 
Molarity of the solution after dilution = 
Volume of the solution after dilution= 
Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:
Volume of solution = 100.0 mL = 0.1 L
Moles of glucose = 
Mass of 0.007248 moles of glucose :
0.007248 mol × 180 g/mol = 1.30464 grams
1.30464 grams of glucose was present in 100.0 mL of final solution.
Answer:
The above compound is an ether. Give thestructure of the product(s) and indicate the major mechanism of the reaction (SN1, SN2, E1 or E2). Indicate stereochemistry when necessary.
The mechanism that explains this transformation begins with the protonation of the ether, which allows the subsequent SN2 attack of the iodide ion. This reaction forms ethyl iodide and ethanol, which is also converted to ethyl iodide by reaction with excess HI.
Explanation:
The SN2 reaction (also known as bimolecular nucleophilic substitution or as an attack from the front) is a type of nucleophilic substitution, where a pair of free electrons from a nucleophile attacks an electrophilic center and binds to it, expelling another group called the leaving group. Consequently, the incoming group replaces the outgoing group in one stage. Since the two reactant species are involved in this slow limiting stage of the chemical reaction, this leads to the name bimolecular nucleophilic substitution, or SN2. Among inorganic chemicals, the SN2 reaction is often known as the exchange mechanism.
Answer:
A liquid with a sharp contact angle (e.g., water on glass) will form a concave meniscus, and the liquid pressure under the meniscus will be smaller than the atmospheric pressure
Explanation:
The phenomenon of capillarity is produced by the action of the surface tension of the fluids and is observed when a small diameter tube is immersed within the fluid. If we pay attention to the result, we can see that, depending on the fluid, two different things can happen, that the liquid rises through the tube and that the level inside the tube is greater than that of the liquid or that the opposite happens.
The case in which the liquid rises above the tube occurs when the liquid "wets". This occurs when the adhesion forces with the walls exceed those of cohesion between the fluid molecules. In this case, the concave side is out of the fluid.
The case where the level of the liquid inside the tube is lower than the level of the liquid occurs when the liquid does not get wet. We remember that the liquid does not get wet when the cohesion forces are greater than those of adhesion. This phenomenon is called capillary depression and the concave angle is for the liquid side and is said to be convex.
Answer:
319 years
Explanation:
For a radioactive decay we have
N = N₀e^-kt , where:
N= Particles Remainng after a time t
N₀ = Particles Initially present
k = ln 2/ t₁/₂ , t₁/₂ is the half life of the radioactive element (Am-241)
We are given that the half-life is 432 yrs, from this inhformation we can calculate the value of k which then will be used to calculate the time Am-241 will take to decay to 40% once we realize we are given the ratio N/N₀.
k = ln 2/ 432 yr = 0.693/ 432 yr = 1.6 x 10⁻³ /yr
N/N₀ = e^-kt
N/N₀ = 60 (amount remaining after 40 % has decayed)/100
N/N₀ = 0.60
0.60 = e-^-kt
taking natural log to both sides of the equation to get rid of e:
ln (0.60) = -1.6 x 10⁻³ /yr x t ∴ t = - ln (0.60) /1.6 x 10⁻³/ yr
t = 0.51 /1.6 x 10⁻³ yr = 319 yrs
To verify our answer realize that what is being asked is how many years it will take to decay 40 %, and we are told the half life , 50 % decay , is 432 years, so for 40 % we will expect it will take less than that which agrees with our resul of 319 years.
