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VashaNatasha [74]
3 years ago
15

A cylindrical tube 13.5 cm high and 4.5 cm in diameter is used to collect blood samples. How many cubic decimeters (dm3) of bloo

d can it hold (V of a cylinder = 72h)? 495.0E-9 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. dm X
Chemistry
1 answer:
Aleks [24]3 years ago
3 0

Answer:

The cylindrical tube can hold 0.215 cubic decimeters of blood.

Explanation:

Diameter of the cylindrical tube = d = 4.5 cm

r = d/2 ,r = 2.25 cm

Height of the cylindrical tube = h = 13.5 cm

Volume of the cylinder = V = \pi r^2h

V=3.14\times (2.25 cm)^2\times 13.5 cm

V=214.6 cm^3=0.2146 dm^3\approx 0.215 dm^3

1 cm^3=0.001 dm^3

The cylindrical tube can hold 0.215 cubic decimeters of blood.

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Among the groups of elements listed below, which have the same number of electrons in their outermost energy levels? C, K, Ca, R
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Explanation:

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Consider 80.0-g samples of two different compounds consisting of only carbon and oxygen. One of the compounds consists of 21.8 g
goldenfox [79]

Answer:

  • <u><em>Ratio of the  mass carbon that combines with 1.00 g of oxygen in compound 2 to the mass of carbon that combines with 1.00 g of oxygen in compound 1 = 2</em></u>

Explanation:

First, detemine the mass of oxygen in the two samples by difference:

  • mass of oxygen = mass of sample - mass of carbon

Item                     Compound 1                        Compound 2

Sample                80.0 g                                    80.0 g

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Oxygen:               80.0 g - 21.8g = 58.2 g         80.0 g - 34.3 g = 45.7 g

Second, determine the ratios of the masses of carbon that combine with 1.00 g of oxygen:

  • For each sample, divide the mass of carbon by the mass of oxygen determined above:

Sample              Mass of carbon that combines with 1.00 g of oxygen            

Compound 1      21.8 g / 58.2 g =  0.375

Compound 2     34.3 g / 45.7 g = 0.751

Third, determine the ratio of the masses of carbon between the two compounds.

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Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling
Reil [10]

Answer:

The boiling  point of a 8.5 m solution of Mg3(PO4)2 in water is<u> 394.91 K.</u>

Explanation:

The formula for molal boiling Point elevation is :

\Delta T_{b} = iK_{b}m

\Delta T_{b} = elevation in boiling Point

K_{b} = Boiling point constant( ebullioscopic constant)

m = molality of the solution

<em>i =</em> Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

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Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}

Total ions after dissociation in solution :

= 3 ions of Mg + 2 ions of phosphate

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m = 8.5 m

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Insert the values and calculate temperature change:

\Delta T_{b} = iK_{b}m

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\Delta T_{b} = 21.76 K

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\Delta T_{b} = T_{b} - T_{b}_{pure}

T_{b}_{pure} = 373.15 K[/tex]

21.76 = T - 373.15

T = 373.15 + 21.76

T =394.91 K

8 0
3 years ago
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