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VashaNatasha [74]
3 years ago
15

A cylindrical tube 13.5 cm high and 4.5 cm in diameter is used to collect blood samples. How many cubic decimeters (dm3) of bloo

d can it hold (V of a cylinder = 72h)? 495.0E-9 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. dm X
Chemistry
1 answer:
Aleks [24]3 years ago
3 0

Answer:

The cylindrical tube can hold 0.215 cubic decimeters of blood.

Explanation:

Diameter of the cylindrical tube = d = 4.5 cm

r = d/2 ,r = 2.25 cm

Height of the cylindrical tube = h = 13.5 cm

Volume of the cylinder = V = \pi r^2h

V=3.14\times (2.25 cm)^2\times 13.5 cm

V=214.6 cm^3=0.2146 dm^3\approx 0.215 dm^3

1 cm^3=0.001 dm^3

The cylindrical tube can hold 0.215 cubic decimeters of blood.

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Alekssandra [29.7K]

Answer: The Kelvin scale is related to the Celsius scale. The difference between the freezing and boiling points of water is 100 degrees in each, so that the kelvin has the same magnitude as the degree Celsius.

Explanation:

Celsius is, or relates to, the Celsius temperature scale (previously known as the centigrade scale). The degree Celsius (symbol: °C) can refer to a specific temperature on the Celsius scale as well as serve as a unit increment to indicate a temperature interval(a difference between two temperatures or an uncertainty). “Celsius” is named after the Swedish astronomer Anders Celsius (1701-1744), who developed a similar temperature scale two years before his death.

K = °C + 273.15

°C = K − 273.15

Until 1954, 0 °C on the Celsius scale was defined as the melting point of ice and 100 °C was defined as the boiling point of water under a pressure of one standard atmosphere; this close equivalence is taught in schools today. However, the unit “degree Celsius” and the Celsius scale are currently, by international agreement, defined by two different points: absolute zero, and the triple point of specially prepared water. This definition also precisely relates the Celsius scale to the Kelvin scale, which is the SI base unit of temperature (symbol: K). Absolute zero—the temperature at which nothing could be colder and no heat energy remains in a substance—is defined as being precisely 0 K and −273.15 °C. The triple point of water is defined as being precisely 273.16 K and 0.01 °C.

7 0
3 years ago
Hypothesis: How will molecular size affect the rate of evaporation and how will this correlate
Simora [160]

A molecular size affects the rate of evaporation when the larger the intermolecular forces in a compound, the slower the evaporation rate and this correlates with temperature change.

Molecular size seems to have an effect on evaporation rates in that the larger a molecule gets or grows from a base chemical formula, its evaporation rate will get slower.

<h3>What is the molecular size?</h3>

This is a measure of the area a molecule occupies in three-dimensional space as this relates to the physical size of an individual molecule.

Hence, we can see that a molecular size affects the rate of evaporation the larger the forces, the lower the rate.

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5 0
2 years ago
Is god real I don’t really no but say yes
vredina [299]

Answer:

Yes

Explanation:

We have been created by him therefore we would not have been created if there was no God.

7 0
2 years ago
Fill in the blanks for the following statements: The rms speed of the molecules in a sample of H2 gas at 300 K will be _________
Anna007 [38]

Answer : The rms speed of the molecules in a sample of H_2 gas at 300 K will be four times larger than the rms speed of O_2 molecules at the same temperature, and the ratio \mu _{rms}(H_2)/\mu _{rms}(O_2) constant with increasing temperature.

Explanation :

Formula used for root mean square speed :

\mu _{rms}=\sqrt{\frac{3RT}{M}}

where,

\mu _{rms} = rms speed of the molecule

R = gas constant

T = temperature

M = molar mass of the gas

At constant temperature, the formula becomes,

\mu _{rms}=\sqrt{\frac{1}{M}}

And the formula for two gases will be,

\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{M_{O_2}}{M_{H_2}}}

Molar mass of O_2 = 32 g/mole

Molar mass of H_2 = 2 g/mole

Now put all the given values in the above formula, we get

\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{32g/mole}{M_{2g/mole}}}=4

Therefore, the rms speed of the molecules in a sample of H_2 gas at 300 K will be four times larger than the rms speed of O_2 molecules at the same temperature.

And the ratio \mu _{rms}(H_2)/\mu _{rms}(O_2) constant with increasing temperature because rms speed depends only on the molar mass of the gases at same temperature.

5 0
3 years ago
I'm just looking for someone to check my answers on this and correct me if I'm wrong :)
Llana [10]
I believe you are right
5 0
3 years ago
Read 2 more answers
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