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3 years ago

14

3.Write the chemical equation for the reaction when methane burns in (2) (a) Sufficient supply of oxygen (b) Insufficient supply

of oxygen

1 answer:

xxMikexx [17]3 years ago

5 0

Answer:

the answer is god

Explanation:

because god created everything therefore hes the answer to everything

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What is the slowest type of mass movement?

LiRa [457]

Answer:

Creep

Creep is the slowest of all the mass movements and moves the most soil out of all the mass movements. The only way to detect soil creep is to observe the fences, buildings, and other surface objects that may be in that area. As the loosened soil moves slowly downslope, these objects will move along with the soil.

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3 years ago

How do u find the volume of a sphere

Alex73 [517]

Answer:

$V=\frac{4}{3} \pi r^3$

Explanation:

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3 years ago

SO3 is an empirical formula for which of the following?

tino4ka555 [31]

Answer:

what are the options

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3 years ago

Consider the following intermediate chemical equations.

geniusboy [140]

<u>Answer:</u> The enthalpy of the overall chemical equation is -205.7 kJ

<u>Explanation:</u>

Hess's law is defined as the law which states that the total amount of heat absorbed or released for a given chemical reaction will remain the same whether the process occurs in one step or several steps.

In this law, a chemical equation is treated as an ordinary algebraic expression that can be added or subtracted to yield the required overall equation.

The enthalpy change or heat of the overall reaction is the summation of the enthalpies or heats of the intermediate reactions involved in the process.

The given overall chemical equation follows:

$CH_4(g)+4Cl_2(g)\rightarrow CCl_4(g)+4HCl(g);\Delta H^o_{rxn}$

The intermediate equations for the above reaction are:

(1) $CH_4(g)\rightarrow C(s)+2H_2(g);\Delta H_1=74.6 kJ$

(2) $CCl_4(g)\rightarrow C(s)+2Cl_2(g);\Delta H_2=95.7kJ$

(3) $H_2(g)+Cl_2(g)\rightarrow 2HCl(g);\Delta H_3=-92.3kJ$

According to Hess law, the enthalpy of the reaction becomes:

$\Delta H^o_{rxn}=[1\times (\Delta H_1)] + [1\times (-\Delta H_2)] + [2\times (\Delta H_3)]$

Putting values in above expression, we get:

$\Delta H^o_{rxn}=[1\times (74.6)] + [1\times (-95.7)] + [2\times (-92.3)]\\\\\Delta H^o_{rxn}=-205.7kJ$

Hence, the enthalpy of the overall chemical equation is -205.7 kJ

8 0

3 years ago

A gas at 42. 0°c occupies a volume of 1. 32 l. if the volume increases to 2. 24 l, what is the new temperature in kelvin?

Nina [5.8K]

the answer is 534.54 kelvin

8 0

2 years ago