Question

Rewrite the expression in the form 4^n4 n 4, start superscript, n, end superscript. (4^{6})(4^{-8})=(4 6 )(4 −8 )=(, 4, start superscript, 6, end superscript, ), (, 4, start superscript, minus, 8, end superscript, ), equals

Answer 1

Answer:

$4^{-2}$

Step-by-step explanation:

Given the expression:  $(4^{6})(4^{-8})$

The two terms have the same base 4. Therefore, we can apply the addition law of indices to simplify.

Addition Law of Indices: $a^x \cdot a^y=a^{x+y}$

Therefore:

$(4^{6})(4^{-8})\\=4^{6+(-8)}\\=4^{6-8}\\=4^{-2}$

Therefore:

$(4^{6})(4^{-8})=4^{-2}$ in the form $4^n$