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Brilliant_brown [7]
2 years ago
12

A grocer buys food from three suppliers. The suppliers deliver every 5 days, 6 days, and 7 days. All three came today. In how ma

ny days will they all deliver on the same day again?
Mathematics
1 answer:
AlekseyPX2 years ago
5 0

Answer:

210

Step-by-step explanation:

For getting this answer we need to find the minimum common multiplier, this is, the smaller number that is multiple of all 5, 6 and 7.

For example, 30 is multiple of both 5 and 6, son in 30 days two suppliers will come, but not the third, as 30 is not a multiple of 7.

Let's try with the next multiple of 5 and 6, this is 60, but is not a multiple of 7.

The next is 90, but again not multiple of 7. Niether are the next: 120, 150, 180.

But when we arrive to 210 we see that, as we are going from multiples of 5 and 6, and 210/7=30, 210 is also multiple of 7.

So, the answer is 210.

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25 feet in 4 seconds; 80 feet in x seconds write a proportion for each phrase and solve it​
ozzi

Answer:

12.8 seconds

Step-by-step explanation:

Create a proportion where x is the number of seconds for 80 feet

\frac{25}{4} = \frac{80}{x}

Cross multiply and solve for x

25x = 320

x = 12.8

So, the answer is 12.8 seconds

3 0
3 years ago
A school held a kiddie carnival to raise PTA. Admission for adults was $8, and admission for children was $5. In the end, 87 peo
andrezito [222]

Answer: 58

Step By Step Explanation: it’s pretty simple all you have to do is take 468 and divide it by 8 and you if you get a decimal such as 48.5 it’s just the first numbers before the decimal

5 0
2 years ago
Is this right? you’re supposed to find FH
Rudik [331]

Answer:

FH=7

Step-by-step explanation:

If the whole thing FG is 22 and HG is 15 you subtract 22-15 and get 7

8 0
3 years ago
Can Someone help me please I don't understand
Sindrei [870]

Answer:

c i think

Step-by-step explanation:

it's c i think

8 0
3 years ago
The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc
BaLLatris [955]

Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

and its midline y_0 is

y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

\omega t =2\pi

\omega (t+14)= 4\pi

giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

8 0
3 years ago
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